Answer:
16 is the awnser or at least I belive
Answer:
Step-by-step explanation:
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The t distribution or Student’s t-distribution is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
Data given
Confidence =0.99 or 99%
represent the significance level
n =16 represent the sample size
We don't know the population deviation 
Solution for the problem
For this case since we don't know the population deviation and our sample size is <30 we can't use the normal distribution. We neeed to use on this case the t distribution, first we need to calculate the degrees of freedom given by:
We know that 
so then 
and we can find on the t distribution with 15 degrees of freedom a value that accumulates 0.005 of the area on the left tail. We can use the following excel code to find it:
"=T.INV(0.005;15)" and we got 
on this case since the distribution is symmetric we know that the other critical value is 
<span>2 and 3/4 punds of roast beef 2 3/4 = (4x2) + 3 /4= 11/4 roast beef
</span><span>1 and 7/8 pounds of turkey 1 7/8 = 15/8 </span>turkey
2 1/16 pounds of salami 2 1/16 33/16 <span>salami
</span><span>if you put 1/4 of pound of meat
</span>then 11/4 roast beef divided by 1/4 = 11/4 x4 = 11 sandwiches roast beef
15/8 turkey<span> divided 1/4 = 15/8 x 4 = 15/2 = 7 sandwishes
</span>
33/16 salami divided <span> 1/4 = 33/16 x 4 = 33/ 4 = 8 sandwiches</span>
Answer:
Step-by-step explanation:
The formula representing the the annual inflation rate r is expressed as
r = (F/P)1/n−1
Where
n represents the the number of years during which the value increases from P to F
A farm increases in value from $800,000 to $1,100,000 over a period of 6 years. This means that
P = $800,000
F = $1,100,000
n = 6
Therefore,
r = (1100000/800000)1/6−1
r = 1.375/5 = 0.275
