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Natalka [10]
3 years ago
6

The box plots show attendance at a school dance competition and school badminton games.

Mathematics
2 answers:
BartSMP [9]3 years ago
5 0

Answer:

The IQR is a better measure of spread for dance competitions than for badminton games.

Step-by-step explanation:

I took the test

Helen [10]3 years ago
4 0

Answer:

The IQR is a better measure of spread for dance competitions than for badminton games.

Step-by-step explanation:

I understand from "Dance Competition box plot has interquartile ranges approximately between 60 and 130" that quartile 1 is at 60 and quartile 3 is at 130, then, the interquartile range (IQR) is 130 - 60 = 70.

Similarly, from Badminton box plot, quartile 1 is at 90 and quartile 3 is at 150, then, the interquartile range is 150 - 90 = 60.

IQR is a measure of statistical dispersion, that is, as IQR increase, spread increase.

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I really don’t understand this
Gemiola [76]

4 pizzas because, 12 slices /3 per person =4 and 16 people /4 = 4 pizzas

7 0
3 years ago
There were two trees growing from seeds in a backyard. One tree grew at a rate of 1//2 of a foot every 2 years. The other grew 4
Ann [662]

Answer:

The height between the two trees will be 1.67 feet.

Step-by-step explanation:

What you do is you take the 1/2 have and times it by 6 because it is every two years that the tree grows 1/2 of a foot. So it will be 3 feet. The other tree grew 4 inches in 3 years so it will be 16 inches you will then have to make the 16 inches into feet to get 1 1/3. You will then minus the 3 feet and the 1 1/3 to get 5/3 or 1.67 feet.

7 0
3 years ago
(1) Ax + By = C (2) Dx + Ey = F Jim is trying to solve the system of equations. He begins by multiplying equation (1) by D and e
attashe74 [19]

Answer:

No, Angela is not correct.

As the method Jim was performing will also lead to the solution.

Step-by-step explanation:

We are given first equation as:

                  Ax + By = C

Second equation is:

                   Dx + Ey = F

Jim solved the equation as:

He begins by multiplying equation (1) by D and equation (2) by A.

and so by subtracting both the equations he will obtain a value of y.

and then put the y-value in any of the given two equations to obtain the value of x.

Angela Method:

you should have multiplied equation (1) by E and equation (2) by B.

and when she will subtract both the equations she will get the value of x first and then when she will put the value of x in any of the given equation she will obtain the value of y.

But both will get a value for x and y.

Hence, the method Jim was performing was also correct.

8 0
3 years ago
Read 2 more answers
Write the equation in vertex form and then find the vertex, focus, and directrix of a parabola with equation x=y^2+18y-2
kakasveta [241]

Answer:

Part 1) The vertex is the point (-83,-9)

Part 2) The focus is the point (-82.75,-9)

Part 3) The directrix is x=-83.25

Step-by-step explanation:

step 1

Find the vertex

we know that

The equation of a horizontal parabola in the standard form is equal to

(y - k)^{2}=4p(x - h)

where

p≠ 0.

(h,k) is the vertex

(h + p, k) is the focus

x=h-p is the directrix

In this problem we have

x=y^{2} +18y-2

Convert to standard form

x+2=y^{2} +18y

x+2+81=y^{2} +18y+81

x+83=(y+9)^{2}

so

This is a horizontal parabola open to the right

(h,k) is the point (-83,-9)

so

The vertex is the point (-83,-9)

step 2

we have

x+83=(y+9)^{2}

<em>Find the value of p</em>

4p=1

p=1/4

<em>Find the focus</em>

(h + p, k) is the focus

substitute

(-83+1/4,-9)

The focus is the point (-82.75,-9)

step 3

Find the directrix

The directrix of a horizontal parabola is

x=h-p

substitute

x=-83-1/4

x=-83.25

6 0
3 years ago
Simplify each problem and expre<br> 1) (2 x 10°) + (5 x 109)
elixir [45]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

(2 · 10⁰) + (5 · 109)

= (2 · 0) + (5 · 109)

=    2     + (5 · 109)

=    2     +    545

=         547

Your answer is 547.

<em>I hope this helps!</em>

3 0
3 years ago
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