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3 years ago

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The student council is planning the school carnival. Each ticket costs $2.50. Explain how to write an equation that represents t

his scenario. Let x represent the number of tickets sold, and y represent the total amount of money raised.

1 answer:

svlad2 [7]3 years ago

7 0

Answer:

me im cute sub scribe to em

Step-by-step explanation:

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Carrie started work at 8 a.m. and left at 1:30 p.m. How many hours of work should she record on her time card for the day?

vagabundo [1.1K]

Start: 8 a. m.
Finish: 1 : 30 p.m. = 13 hours 30 minutes
13 h 30 min - 8 h = 5 h 30 min
She should record 5 hours and 30 minutes on her time card for the day.

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Factor out the greatest common factor. <br>2f^3-8f^2

ella [17]

Answer:

Step-by-step explanation:

8f² = 2³f²

GCF of 2f³ and 8f² = 2f²

2f³ - 8f² = 2f²(f - 4f)

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3 years ago

Are these expressions equivalent 3(5b-2) and 8b-5

Pavel [41]

No, if you multiply the factors in 3(5b-2) the equivalent expression would be 15b-6

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Consider the following hypothesis test. : : The following results are for two independent samples taken from two populations. Ex

I am Lyosha [343]

Answer:

$z = -1.53$ --- test statistic

$p = 0.1260$ --- p value

Conclusion: Fail to reject the null hypothesis.

Step-by-step explanation:

Given

$n_1 = 80$ $\bar x_1= 104$ $\sigma_1 = 8.4$

$n_2 = 70$ $\bar x_2 = 106$ $\sigma_2 = 7.6$

$H_o: \mu_1 - \mu_2 = 0$ --- Null hypothesis

$H_a: \mu_1 - \mu_2 \ne 0$ ---- Alternate hypothesis

$\alpha = 0.05$

Solving (a): The test statistic

This is calculated as:

$z = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2} }}$

So, we have:

$z = \frac{104 - 106}{\sqrt{\frac{8.4^2}{80} + \frac{7.6^2}{70} }}$

$z = \frac{104 - 106}{\sqrt{\frac{70.56}{80} + \frac{57.76}{70}}}$

$z = \frac{-2}{\sqrt{0.8820 + 0.8251}}$

$z = \frac{-2}{\sqrt{1.7071}}$

$z = \frac{-2}{1.3066}$

$z = -1.53$

Solving (b): The p value

This is calculated as:

$p = 2 * P(Z < z)$

So, we have:

$p = 2 * P(Z < -1.53)$

Look up the z probability in the z score table. So, the expression becomes

$p = 2 * 0.0630$

$p = 0.1260$

Solving (c): With $\alpha = 0.05$ , what is the conclusion based on the p value

We have:

$\alpha = 0.05$

In (b), we have:

$p = 0.1260$

By comparison:

$p > \alpha$

i.e.

$0.1260 > 0.05$

So, we fail to reject the null hypothesis.

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3 years ago

Y = -(x+2)* - 3<br> Plot on a graph

Orlov [11]

Answer:

y=-x-2*-3

Step-by-step explanation:

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