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Irina18 [472]
2 years ago
12

The cost of 10 yearbooks $250 what is the cost of one yearbook

Mathematics
2 answers:
Ierofanga [76]2 years ago
6 0
$25 per yearbook

The cost is x and the amount is 10
So the equation is 10x=$250
Divide 250 by 10 and get 25
Leviafan [203]2 years ago
6 0
The per-yearbook cost is
   $250/10 = $25

_____
Whether you can actually purchase one yearbook for that price depends on a number of factors.
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Youre amazing!!! could you help me? 50 points!!! Write an expression that can be used to produce vector d from vector c, and exp
andrew-mc [135]

Answer:

Multiply vector c by the scalar -1/2.

Step-by-step explanation:

Look at vector c.

It has an x component of 4 and a y component of 4.

You can write vector c as a sum of its components using unit vectors in the x direction (i) and in the y direction (j).

c = 4i + 4j

Now look at vector d, and write it also as a sum of its x and y components.

d = -2i - 2j

Now ask yourself, what operation do I do to 4 to end up with -2?

One answer is to multiply 4 by -1/2.

d = (-1/2)c = (-1/2)(4i) + (-1/2)(4j) = -2i - 2j

That worked. By multiplying vector c by the scalar -1/2, you end up with vector d.

8 0
2 years ago
HELP PLEASE 3. Simplify the expression (5 points)<br> [(7 + 3) • 5 - 4] = 2 + 2
krok68 [10]

Answer: 46 or 46=4

Step-by-step explanation:

Do what's in the Parenthesis first so 7+2=10 which now give you the equation

[10x 5-4]=2+2

Now we Multiply so we do 10x5 which is 50 so that now gives us the equation[50-4]=2+2

Now we add the 2+2 which is 4 giving us the equation [50-4]=4

Now we subtract 50-4 giving 46

46=4

5 0
3 years ago
Read 2 more answers
Please someone help me ASAP
nasty-shy [4]

Answer:

A

Step-by-step explanation:

FV=PV(1+i)^t

2500(1+.03)^4

A

3 0
2 years ago
Read 2 more answers
Round 43.628 to the thousands place. A. 40.000 O O B. 43.000 O O C. 43.600 D. 44.000
VARVARA [1.3K]

Answer:

A) 40000

Step-by-step explanation:

this is the answer to your question

6 0
1 year ago
Given that tan θ ≈ −0.087, where 3 2 π &lt; θ &lt; 2 , π find the values of sin θ and cos θ.
elena-s [515]

Answer:

  • sin θ ≈ -0.08667
  • cos θ ≈ 0.99624

Step-by-step explanation:

Straightforward use of the inverse tangent function of a calculator will tell you θ ≈ -0.08678 radians. This is an angle in the 4th quadrant, where your restriction on θ places it. (To comply with the restriction, you would need to consider the angle value to be 2π-0.08678 radians. The trig values for this angle are the same as the trig values for -0.08678 radians.)

Likewise, straightforward use of the calculator to find the other function values gives ...

  sin(-0.08678 radians) ≈ -0.08667

  cos(-0.08678 radians) ≈ 0.99624

_____

<em>Note on inverse tangent</em>

Depending on the mode setting of your calculator, the arctan or tan⁻¹ function may give you a value in degrees, not radians. That doesn't matter for this problem. sin(arctan(-0.087)) is the same whether the angle is degrees or radians, as long as you don't change the mode in the middle of the computation.

We have shown radians in the above answer because the restriction on the angle is written in terms of radians.

_____

<em>Alternate solution</em>

The relationship between tan and sin and cos in the 4th quadrant is ...

  \cos{\theta}=\dfrac{1}{\sqrt{1+\tan^2{\theta}}}\\\\\sin{\theta}=\dfrac{\tan{\theta}}{\sqrt{1+\tan^2{\theta}}}

That is, the cosine is positive, and the sign of the sine matches that of the tangent.

This more complicated computation gives the same result as above.

4 0
3 years ago
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