Square ABCD and square EFGH will reflect onto themselves across 8 lines of reflection
Applying the inscribed angle theorem, the measure of arc AB that doesn't go through point C is: 100 degrees.
<h3>What is the Inscribed Angle Theorem?</h3>
Based on the inscribed angle theorem, if ∅ is the inscribed angle measure, the measure of the central angle subtended by the same arc equals 2(∅).
m∠BAC = 40 degrees.
Central angle = 2(40) = 80 degrees [based on the inscribed angle theorem]
Corresponding arc BC = 80 degrees.
Arc AC through point B = 180 degrees [half circle]
Arc AB = 180 - arc BC = 180 - 80 = 100 degrees.
Learn more about the inscribed angle theorem on:
brainly.com/question/3538263
#SPJ1
Answer:
144°
96+48(further away angles)
Answer:
y = 3x
Step-by-step explanation:
The exact equation for the climb would be y = (x-3)^2 + 9, however, a rough line that represents the climb is y = 3x.
Find the slope between (0, 0) and (3, 9) and we get m = 3. Plug it into y-int form and you get the line.
Answer:
see explanation
Step-by-step explanation:
The opposite angles of an inscribed quadrilateral are supplementary, thus
5x + 20 + 7x - 8 = 180
12x + 12 = 180 ( subtract 12 from both sides )
12x = 168 ( divide both sides by 12 )
x = 14
Thus
∠ RQP = 10x = 10(14) = 140°
∠PSR = 180° - 140° = 40° ( opposite angles are supplementary )
∠ SRQ = 7X - 8 = 7(14) - 8 = 98 - 8 = 90°
∠ QPS = 5x + 20 = 5(14) + 20 = 70 + 20 = 90°
