The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola<span>. We determine as follows:
y = 2x^2 - 4x + 1
</span>
y = a(x – h)2<span> + k
</span>
y = 2(x^2 - 2x) + 1
y = 2(x^2 - 2x + 1) + 1 - 1
y = 2(x - 1)^2
Therefore, the line of symmetry passes through the vertex ( 1, 0) with an equation x = 1.
So here is how you solve for the answer.
Firstly, you solve for the Area of Rectangle A.
The formula for Area is Length x width.
So A = (2x + 6)(3x) and the result is: 6x^2 + 18x
Now, let y be the width of rectangle B.
<span>(x+2) (y) = 6x^2 + 18x + 12
(x+2) y = 6(x+1)(x+2)
y = 6(x+1)
</span>So the final answer would be width is 6x + 6. The answer is the third option. Hope this answer helps.
If it is not contained in a fraction write it as one over the variable with a positive exponent
ex. 2^-1 = 1/2. 3^-2 = 1/3² = 1/9
if it is in the denominator of a fraction move it to the numerator and make it positive
ex. 1/4^-1 = 4. 2/3^-2 = 2*3² = 18
if it is in the numerator...you get the picture
ex 6^-2/3 = 1/3*6² = 1/108
hope that helps
Answer:
y-intercept is (0, 2).
Step-by-step explanation:
The y-intercept occurs when x = 0 so:
2(0) + 3y = 6
y = 6/3 = 2.
So the y-intercept is (0, 2).
