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3 years ago

What is the solution to the system of equations graph below?

Mathematics

2 answers:

kirza4 [7]3 years ago

7 0

Answer:

Correct option is:

B. (-2,3)

Step-by-step explanation:

The solution of the system of the equations graphed is that point on which the two graphs meet.

Here, the system of equations:

y=4x+11

y= -2x-1

are graphed and as we can clearly see from the graph the two graphs meet at a point (-2,3)

So, solution is (-2,3)

Hence, Correct option is:

B. (-2,3)

mestny [16]3 years ago

6 0

Answer: B. (-2, 3)

Step-by-step explanation: The two lines have the same solution where both lines intersect. So, if you look at the point on the graph where the two lines intersect, and count the tick marks on the number lines, the point is clearly located at (-2, 3).

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3 years ago

Read 2 more answers

Tell me how you got the answer

Anvisha [2.4K]

Answer:

x = 18; y = 20

Step-by-step explanation:

Triangles KLM and KNO are similar, so the ratios of the lengths of corresponding sides are equal.

KL/KN = LM/NO

10/30 = 6/x

Cross multiply.

10x = 6 * 30

10x = 180

x = 18

KL + LN = KN

10 + y = 30

y = 20

8 0

3 years ago

Please help i will mark brainliest

Evgen [1.6K]

Answer:

2. $\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$

3. $\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]$

4. $\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]$

Step-by-step explanation:

2. This matrix is easy, as it just requires addition.

$\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$ + $\left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]$ = $\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$

3. This matrix requires for the matrices to be multiplied first, then added.

$\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]$ + $\left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]$ = $\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]$

4. Here we can add the last 2 matrices to find x.

$\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]$ + $\left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]$ = $\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]$