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Bas_tet [7]
3 years ago
15

What biome is the worlds largest and contains mostly coniferous trees

Biology
1 answer:
n200080 [17]3 years ago
8 0
The answer is a deciduous forest.
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What will most likely happen to the first finch with the big beak if it had been born on the continent of south America
Bess [88]
It would not have any finches to mate with 

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3 years ago
HELP PLEASE!!! ASAP I NEED QUICKLY!! DBA List the helpful interactions. List the harmful interactions.
Svetach [21]

1. Symbiosis is the interaction between two different living organisms living together to survive.

2. Parasitism is the relationship between two species of plants or animals in which one benefits at the expense of the other, sometimes without killing the host organism.

Example: Tapeworms attach themselves to the insides of the intestines of animals.They get food by eating the host's partly digested food, depriving the host of nutrients. Another example is fleas. they harm their hosts, by biting their skin, sucking their blood, and causing them to itch.

3. A predator is an animal that preys on other animals, usually for food.

Example: A lion or a bear.

4. The definition of prey is where one organism, the predator, kills and eats another organism.

Example: The prey to a lion would be a zebra, and the prey to a bear would be a fish.

5. Mutualism is where two different species live together to survive at each others advantage.

Example: Oxpeckers and rhinos.

6. Commensalism is where one organism benefits and the other is not harmed or benefited.

Example: Barnacles and Whales.

7. Predation helps keep herbivores from growing into too large of crowds, and predation keep the population of animals in general in check.

8. Competition both within and between species is an important topic in ecology, especially community ecology.

9. This is in your own words :)

10. I don't know what article you read

<em>I hope this all helps :D</em>



3 0
3 years ago
The blight that so significantly affected the sponging industry occurred when?
Serjik [45]

Answer: 5,329 lol I just need points

Explanation:

7 0
3 years ago
Read 2 more answers
How does the picture tie into the poem poem by dickinson
lisabon 2012 [21]

Answer:

wheres the picture

Explanation:

5 0
3 years ago
A student examines a thin section of an onion-root tip and records the number of cells that are in each stage of the cell cycle.
Maksim231197 [3]
The answer is 0.92 hour, which is the average duration in an hour of anaphase in the cycle.

The information required to answer the problem is the average duration of each stage of the cell cycle.The numbers of cells in different stages of the cell cycle and the time required for a complete cell is the information that should be provided in order to solve the problem. 

The problem is solved in two steps. In which first is to calculate the proportions of cells in each stage of the cell cycle, which correspond to the amount of time that an average cell spends in each stage. For example, if cells spend 90% of their time in interphase, then at any given moment, 90% of the cells will be in interphase. The second step is to convert the proportions into lengths of time which are completed by multiplying the proportions by the total time of the cell cycle (22 hours).

1. Calculate the proportion of cells at each stage. The proportion of cells at each stage is equal to the number of cells found in that stage divided by the total number of cells observed. Note that the total of all the proportions should equal 1.0. 

• Interphase 94/120 = 0.783
• Prophase 14/120 = 0.117
• Prometaphase 3/120 = 0.025
• Metaphase 3/120 = 0.025
• Anaphase 5/120 = 0.042
• Telophase 1/120 = 0.008

Check the calculations by making sure that the proportions sum to 1.0

2. Determine the average duration of each stage. Note that the total time for all stages should equal 22 hours. To determine the average duration of each stage, multiply the proportion of cells in each stage by the time required for the entire cell cycle.

• Interphase 0.783 × 22 hours = 17.23 hours
• Prophase 0.117 × 22 hours = 2.57 hours
• Prometaphase 0.025 × 22 hours = 0.55 hour
• Metaphase 0.025 × 22 hours = 0.55 hour
• Anaphase 0.042 × 22 hours = 0.92 hour
• Telophase 0.008 × 22 hours = 0.18 hour
8 0
3 years ago
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