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victus00 [196]
3 years ago
10

Graph the Inequality y>2x-5 on set of axis

Mathematics
2 answers:
vova2212 [387]3 years ago
8 0
Https://www.quickmath.com/webMathematica3/quickmath/graphs/inequalities/basic.jsp#
timofeeve [1]3 years ago
6 0
You already have it in slope-intercept form, so point your y-intercept on the graph at 5, then move up 2 points and to the right one point - <em>slope is rise over run - </em>. Then move down one left one - <em>slope can be written as positive over positive and negative over negative because they simplify to positive.</em>
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Answer:

156

Step-by-step explanation:

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Somebody please help me with this​
satela [25.4K]

Answer:

15/56

Step-by-step explanation:

5 people have a license

3 people don't

? = Probability that first person has a license and second does not

We can divide the problem into two sections, the first being the probability of the first person having a license, and the second section is the probability that the second person doesn't have a license.

P1 = Probability of the first person having a license, there are 5 out of 8 person having a license, thus P1 = 5/8.

P2 = Probability of the second person having a license. There are 3 people not having a license, out of 8-1 = 7 persons available, since one is taken already from the first choice, therefore P2 = 3/7.

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2 years ago
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san4es73 [151]
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3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
Sunny_sXe [5.5K]

Answer:

<h2>\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }</h2>

First option is the correct option.

Step-by-step explanation:

\frac{2x + 5}{ {x}^{2} - 3x }  -  \frac{3x + 5}{ {x}^{3} - 9x }  -  \frac{x + 1}{ {x}^{2} - 9 }

Factor out X from the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x( {x}^{2}  - 9)}  -  \frac{x + 1}{ {x}^{2}  - 9}

Using {a}^{2}  -  {b}^{2}  = (a - b)(a + b) , factor the expression

\frac{2x + 5}{x(x - 3)}  -  \frac{3x + 5}{x(x - 3)(x + 3) }  -  \frac{x + 1}{(x - 3)(x + 3)}

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}

Multiply the parentheses

\frac{2 {x}^{2}  + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

\frac{2 {x}^{2}  + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}

Distribute -x through the parentheses

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Using {a}^{2}  -  {b}^{2}  = (a + b)(a - b) , simplify the product

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Collect like terms

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Subtract the numbers

\frac{ {x}^{2}  + 7x + 10}{ x({x}^{2}   - 9)}

Distribute x through the parentheses

\frac{ {x}^{2}  + 7x + 10}{ {x}^{3}  - 9x}

Write 7x as a sum

\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }

Factor out X from the expression

\frac{x(x + 5) + 2x + 10}{ {x}^{3}  - 9x}

Factor out 2 from the expression

\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }

Factor out x + 5 from the expression

\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }

Hope this helps...

Best regards!!

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Step-by-step explanation:

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