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daser333 [38]
4 years ago
11

If a = 5, b = 5 and c = 10, what is the value of ac / 2b ?

Mathematics
1 answer:
Sophie [7]4 years ago
3 0

Answer:

The answer is 5 .

Step-by-step explanation:

You have to substitute the values of a, b and c into the expression :

\frac{ac}{2b}

Let a = 5,

Let b = 5,

Let c = 10,

\frac{5 \times 10}{2 \times 5}

=  \frac{50}{10}

= 5

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The nth taylor polynomial for the given function is

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Given:

f(x) = ln(x)

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nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

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f'(x) = 1/x ⇒ f'(5) = 1/5

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f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

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P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

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