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Pavlova-9 [17]
3 years ago
5

Factorise 3x^2-22x+7

Mathematics
1 answer:
Svet_ta [14]3 years ago
3 0

Answer:

(3x+7)(x+5)

Step-by-step explanation:

i think lol

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Write an algebric pharse for five times a number increased by nine.<br><br> i need help
trasher [3.6K]

Answer:

Step-by-step explanation:

five times a number increased by nine is

5x+9

x is the unknown number being multiplied by 5

increase= add

so add by 9

6 0
3 years ago
The students in Mr.​ Kim's class are discussing how to apply the properties of equality. Jared started with the equation 10 - 4=
iVinArrow [24]

<u>Answer</u>:

Jared is right.

<u>Explanation</u>:

proof 1:

10 - 4 = 6

6 = 6

second proof:

10-3 - 4 = 6 - 3

10 - 7 = 3

3 = 3

third proof:

10 - 4 - 3 = 6 - 3

10 - 7 = 3

3 = 3

Hence for all LHS = RHS proved and Jared is correct.

7 0
2 years ago
Please answer these questions and have the work shown:
ahrayia [7]

Answer:

number one 50 I think and 3 is 75 not positive but I hope it helps

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
if the cost price of 10 tables is equal to the selling price of 16 tables , find out the gain or loss percentage​
Dovator [93]

Hi,

To solve this problem, Let us take the LCM of 10 and 16 which will come 80.

Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n

According to the question, CP of 10 tables is equal to the SP of 16 tables, then

the SP of 16 tables will also be ₹ n.

So, SP of 80 tables will be ₹ 5n

So, Loss = CP-SP

→ 8n - 5n = ₹ 3n

Loss%= (3n×100)/8n

Loss%= 37.5%.

Hence the correct answer will be a <u>loss of 37.5%.</u>

4 0
3 years ago
A committee of 3 is being formed randomly from the employees at a school: 5 administrators, 34 teachers, and 4 staff. What is th
pav-90 [236]

Answer:0.000810

Step-by-step explanation:

Given

A committee of 3 members is formed using

5 Admin, 34 teachers, and 4 staff

Favorable outcomes are selecting 3 members as Administrators

total members =5+34+4=43

Probability is given by

\Rightarrow P=\dfrac{\text{Favorable}}{\text{Total}}

\Rightarrow P=\dfrac{^5C_3}{^{43}C_3}=\dfrac{10}{43\times 41\times 7}\\\\\Rightarrow P=\dfrac{10}{12,341}=0.000810

6 0
3 years ago
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