Question

One number is times a first number. A third number is 100 more than the first number. If the sum of the three numbers is ​, find the numbers. The three numbers are nothing. ​(Use a comma to separate answers as​ needed.)

Answer 1

Question:

One number is 7 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 505, Find the numbers.

Answer:

The numbers are 45, 315 and 145

Step-by-step explanation:

Represent the three numbers with A, B and C

Required

Find A, B and C

From the first statement;

$B = 7 * A$

$B = 7A$ --- (i)

From the second;

$C = 100 + A$  ---- (ii)

From the third;

$A + B + C = 505$  ---- (iii)

Substitute 7A for B and 100 + A for C in (iii)

$A + 7A + 100 + A = 505$

Collect like terms

$A + 7A + A = 505 - 100$

$9A = 405$

Divide both sides by 9

$A = 45$

Substitute 45 for A in (i)

$B = 7A$

$B = 7 * 45$

$B = 315$

Substitute 45 for A in (ii)

$C = 100 + A$

$C = 100 + 45$

$C = 145$

Hence, the numbers are 45, 315 and 145