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sashaice [31]
3 years ago
15

Can someone help with this math question please

Mathematics
1 answer:
Naddik [55]3 years ago
3 0
One point of the line is given to be (5, -1) and second point is the y-intercept of the line x - 3y = 6

We can write this equation as:

x-6=3y \\  \\ 
y= \frac{1}{3}x-2

So, the y-intercept of the line is -2. 

Now we have two points for the new line (5, -1) and (0, -2). Using these we can find the slope

Slope=m= \frac{-2+1}{0-5}= \frac{1}{5}

Using the slope and the point (0, -2) we can write the equation in slope intercept form as:

y= \frac{1}{5}x-2

Thus the answer to this question is option C. Slope for the new line is 1/5 and the y-intercept is -2
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Janet bought4/5 of a pound of walnuts. Her family ate 1/3 of a pound. How much is left?
Serga [27]

this just wants us to calculate 4/5-1/3

make common denom

4/5 times 3/3=12/15

1/3 times 5/5=5/15

4/5-1/3=12/15-5/15=(12-5)/15=7/15

7/15lb is left

6 0
4 years ago
Read 2 more answers
An initial number of bacteria presented in a culture is 1,000. This number triples every 30 minutes. Write a function expressing
Svetlanka [38]
Tripiling time is
A=P(3)^ \frac{t}{r}
t=time elapsed
r=tripling time
P=initial amount


so


A=1000(3)^ \frac{t}{30}
when time is measured in minutes
if measured in hours then

A=1000(3)^{2t} orA=1000(9)^{t}
8 0
4 years ago
Find the area of a triangle with legs that are 9mm 6mm and 12mm
Sidana [21]

Here we are given the three sides of the triangle.

So we have Heron's formula to find its area.

Heron's formula is given by :

A= \sqrt{S(S-A)(S-B)(S-C)}

where A, B and C are sides of triangle and S is semi perimeter which is given by,

S= \frac{A+B+C}{2}

plugging values of A, B and C to find S

S= \frac{9+6+12}{2}

S=13.5

Now plugging values of A, B , C and S in Heron's formula

A= \sqrt{13.5(13.5-9)(13.5-6)(13.5-12)}

A=26.14 mm²

Answer: Area of triangle is 26.14 mm².



6 0
3 years ago
Plzzzz help mehh its scientific notation and im putting alot o point for it
s344n2d4d5 [400]
(7.2\cdot10^7)^2=7.2^2\cdot(10^7)^2=51.84\cdot10^{14}=\boxed{5.184\cdot10^{15}}=\\
\boxed{5,184,000,000,000,000}
5 0
3 years ago
A certain forest covers an area of 4800 km^2 . Suppose that each year this area decreases by 5.25% . What will the area be after
9966 [12]

Answer:

the area after 6 years is  3,473 km^2

Step-by-step explanation:

The computation of the area after 6 years is as follows:

= Area × (1 - decreased percentage)^number of years

= 4,800 km^2 × (1 - 5.25%)^6

= 4,800 km^2 × 0.9475^6

= 3,473 km^2

Hence, the area after 6 years is  3,473 km^2

5 0
3 years ago
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