Can someone help with this math question please
1 answer:
One point of the line is given to be (5, -1) and second point is the y-intercept of the line x - 3y = 6
We can write this equation as:
So, the y-intercept of the line is -2.
Now we have two points for the new line (5, -1) and (0, -2). Using these we can find the slope
Using the slope and the point (0, -2) we can write the equation in slope intercept form as:
Thus the answer to this question is option C. Slope for the new line is 1/5 and the y-intercept is -2
We can write this equation as:
So, the y-intercept of the line is -2.
Now we have two points for the new line (5, -1) and (0, -2). Using these we can find the slope
Using the slope and the point (0, -2) we can write the equation in slope intercept form as:
Thus the answer to this question is option C. Slope for the new line is 1/5 and the y-intercept is -2
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Answer:
Look to the attached graph
Step-by-step explanation:
* Lets revise how to graph the quadratic function
- Find the vertex of it
- Find the y-intercept
- Find the x-intercept
∵ f(x) = (x - 5)² + 1 ⇒ the completing square form
- The completing square form for any quadratic is
( x - h)² + k, where h and k are the coordinate of the vertex point
* Lets compare the two forms
∵ (x - h)² + k = (x - 5)² + 1
∴ h = 5 and k = 1
∴ The vertex of the parabola is (5 , 1)
- To find the x-intercept put f(x) = 0
∵ (x - 5)² + 1 = 0 ⇒ subtract 1 from both sides
∴ (x - 5)² = -1 ⇒ the square can not give -ve number
∴ The parabola does not intersect the x-axis
- To find the y-intercept put x = 0
∵ f(0) = (0 - 5)² + 1 = 25 + 1 = 26
∴ The parabola intersects the y-axis at point (0 , 26)
- The parabola is opened upward because the coefficient of x² is +ve
* Now lets graph it
- Look to the attached graph
