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mafiozo [28]
2 years ago
15

What is the radius of the sun?

Mathematics
1 answer:
Harrizon [31]2 years ago
5 0
432,288 miles.
Google something like this lol
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The density d kg/m3 of a cube of mass m kilograms and side length x meters is given by the formula:  What is the value of d if
bearhunter [10]

Answer:

5000kg/m3

Step-by-step explanation:

Its easy to get the answer of a question from the unit.

So, it will be mass over metre cube.

Therefore, m=40kg x= (0. 2)^3 =0. 008m

40/0. 008 = 5000kg/m^3

6 0
2 years ago
I need help with point slope formula bad
NISA [10]
Ok so this question:
y + 1 = - ( x - 2 )        (distribute the negative inside the parenthesis)
y + 1 = -x + 2             (substitute the y= -1)
-1 + 1 = -x + 2
0 = -x + 2                   (take two to the other side)
-2 = -x                        (divide the negative away from x)
2 = x

3 0
2 years ago
What is the definition of a perfect cube?
Rom4ik [11]
<span>The definition of a perfect cube is a number that is the result of multiplying an integer by itself three times
Hope it helps</span>
3 0
2 years ago
The formula for glue says add 45 mL of Hardner to each container of resin how much Hardner should be added to 18 containers of r
Luden [163]

Answer:

810 mL of hardener

Step-by-step explanation:

You need 45 mL of hardener for each container and you have 18 containers so:

45 x 18 = 810 mL

7 0
3 years ago
Steve and Abby purchased a set of vases to place on a 12 foot long mantel above their fireplace. They want to place one vase 1/4
Nonamiya [84]

Answer: One vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

Step-by-step explanation:

You know that lenght of the mantel above their fireplace is 12 feet.

They want to place one vase \frac{1}{4} of the distance from one end of the mantel. This distance in feet is:

distance_{vase1}=(12feet)(\frac{1}{4})\\\\distance_{vase1}=3feet

 They want to place the other vase \frac{3}{4} of the distance from the same end of the mantel. Therefore, this distance in feet is:

distance_{vase2}=(12feet)(\frac{3}{4})\\\\distance_{vase2}=\frac{36feet}{4}\\\\distance_{vase2}=9feet

Therefore, one vase should be placed 3 feet from the end of the mantel and the other vase should be placed 9 feet from the same end.

5 0
3 years ago
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