The equation of a straight line is given by:
y = mx + c
where m is the slope and c is the y-intercept.
From the given graph, the y-intercept is 1.
The slope of a straight line is given by:
Where
and
are two points on the line.
From the graph, (0, 1) and (14, 8) are two points on the line, thus:
Therefore, the equation representing the graph is
Answer:
y = - 4x
Step-by-step explanation:
The slope-intercept form of a line is y = mx + b. In this case, m is - 4 and no b value is given.
Undefined slope is rise/0
run is equal to 0
that means it doesn't go left or right
means it is vertcal
means it is x=somethig
(x,y)
(-6,4)
x=-6 is the equation
oh, forgot about standard form
standard form is
ax+by=c
so
x+0y=-6 would be the equation in standard form
Hello there,
The outlier of the data set is 92. Lets first find everything with the outlier.
Mean: 60.08
Median: 57
Mode: 52
Range:46
Now let's take out the outlier of the set and see the difference.
Mean: 54.27
Median:56
Mode: 52
Range: 15
So as we can see without the outlier everything is closer together. The outlier shouldn't be included because that makes the entire set screwed up. The data is more accurate without the outlier.
Hope this helps!
Answer:
It will take 6 hours for the new pump to drain the pool.
Step-by-step explanation:
As the complete question is not given, the complete question is found online and is attached herewith
Let the rate of new pump is given as x=W/t_1
Let the rate of the old pump is given as y=W/t_2
it is given that the time t_2=2t_1
So by substituting the values of t_2 in the rate equation of y
y=W/2t_1
y=(W/t_1*2)=x/2
Also the total rate of both the pumps is given as W/t3 where t3 is given as 4 hours so the equation becomes
x+y=W/4
x+x/2=W/4
3x/2=W/4
As x=W/t_1
3W/2t_1=W/4
Now as W is same on both sides so
3/2t_1=1/4
12=2t_1
t_1=6 hours
So it will take 6 hours for the new pump to drain the pool.
