Two positive integers have gcd (a, b) = 15 and lcm (a, b) = 90. Those two numbers are 15 and 90 or 30 and 45.
Suppose we have 2 positive integers, a and b, then:
gcd (a, b) = the greatest common divisor = common prime factors of a and b
lcm (a, b) = the least common multiple = multiplication of the greatest common prime factors of a and b
In the given problem:
gcd (a, b) = 15
prime factorization of 15:
15 = 3 x 5
Hence,
a = 3 x 5 x ....
b = 3 x 5 x ....
lcm (a, b) = 90
prime factorization of 90:
90 = 3 x 5 x 2 x 3
Therefore the possible pairs of a and b are:
Combination 1:
a = 3 x 5 = 15
b = 3 x 5 x 2 x 3 = 90
Combination 2:
a = 3 x 5 x 2 = 30
b = 3 x 5 x 3 = 35
We can conclude the two integers are 15 and 90 or 30 and 45.
Learn more about gcd here:
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Step-by-step explanation:
here's the solution,
in the given figure , sum of all angles formed with O measures 360°
because, it forms a complete angle
so,
=》mPOQ + mQOR + mROS + mSOT + mTOP = 360°
=》mPOQ + mQOR + mROS + mSOT + mTOP = (90° × 4)
=》mPOQ + mQOR + mROS + mSOT + mTOP = 4 × right angle
(cuz.. right angle = 90°)
It’s 4 because it’s in front of X
S=k, a=4k-2
Annika rides her bike so she must travel some positive distance, ie a>0 so:
4k-2>0
4k>2
k>1/2 and that k is how far Sam rode, so Sam must ride his bike more than 1/2 kilometer.
In a parallelogram, opposite sides are parallel and equal . So to prove JKLM a parallelogram, we need to satisfy both criterias . And only the last option stand up on both criterias that is opposite sides are parallel and equal .
So the correct option is the last option .
