It would be f(t)= 25^t+1
If you plugged in '2' as 't',
25^2+1= 15, 625 which uses the second day of the bacteria.
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
It's 48cm2 all u do is 6x8 divided by 2
Answer: 8
Step-by-step explanation:
2 To convert to a percent, multiply the decimal by 100.
8\times 100=800
8×100=800
800
800%
Answer:
Yes
Step-by-step explanation:
Because 17 times 32 equals 224