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laiz [17]
3 years ago
15

Please help. Ignore The answer I have selected. I'm not sure if it's correct

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0
Yes, I believe that is correct.
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Wesley's laundry basket has a rectangular base with an area of 200 square inches. The basket has a height of 24 inches and it is
ozzi

Answer:

4800 cubic Inches

Step-by-step explanation:

Wesley's laundry basket has a rectangular base with an area of 200 square inches. The basket has a height of 24 inches and it is full of clothes. What is the volume of Wesley's laundry basket?

The volume of Wesley's Rectangular laundry basket = Area of the Base × Height of the basket

Base area = 200 square inches

Height of the basket = 24 inches

Volume of the basket = 200 square inches × 24 inches

= 4800 cubic Inches

7 0
3 years ago
How to solve a quadratic equation when c=0
kherson [118]
Lets say we have a quadratic equation:

3x^2 + x + 0 = 0

Now, since if we add or subtract 0 from something, the original value stays the same, which means we can write the equation as 3x^2 + x = 0 and ignore the “+0”.

In these kinds of equations, you /can/ use the quadratic formula, but theres a much quicker way. If we factor 3x^2 + x, we get x(3x + 1) = 0. Here, x has two possible values — since the result of the multiplication is 0, that means that either one expression or the other must equal 0. In essence:

If x(3x+1) = 0 then x = 0 or 3x+1 = 0
One of the solutions is that x = 0. Lets find the other.

3x+1=0
3x= -1
x = -1/3

So x1 = 0 and x2 = -1/3. So basically you solve these equations using basic factorization. :)
6 0
3 years ago
This the question answer fasssssssssssst plz
laila [671]

Answer:

sloooooooooooooooooooooooooowwwwww

6 0
3 years ago
Please answer quick..
rjkz [21]

Answer:

10

Step-by-step explanation:

the length is 2 and the width is 5 so 2·5=10

6 0
3 years ago
Consider a triangle...
exis [7]

Answer:

1. Triangle: B = 47.0° , C = 103.05° , c = 2.53 cm

2. Lake: c = 1105.31 ft

Step-by-step explanation:

Law of Sine Formula:\frac{sin(A)}{A} = \frac{sin(B)}{B} = \frac{sin(C)}{C}

Given: A = 30° , a = 1.3 cm , b = 1.9 cm

\frac{sin(30)}{1.3} = \frac{sin(B)}{1.9} = \frac{sin(C)}{C}

Solving for sin(B). Cross Multiply.

\frac{sin(30)}{1.3} = \frac{sin(B)}{1.9}\\1.3*sin(B)=1.9*sin(30)\\sin(B)=\frac{1.9*sin(30)}{1.3} \\

B = sin^-1( \frac{1.9*sin(30)}{1.3} )

B ≈ 46.9509202

B = 47.0°

Solve for C°

A° + B° + C° = 180°

30° + 46.95° + C° = 180°

C° = 180° - 30° - 46.95°

C° = 103.05°

Solve for sin(C)

\frac{sin(30)}{1.3} = \frac{sin(103.05)}{C}\\

Cross Multiply

C*sin(30)=1.3*sin(103.05)\\C=\frac{1.3*sin(103.05)}{sin(30)}

C ≈ 2.532850806

C = 2.53 cm

Law of Cosine Formula: c^2=a^2+b^2-2*a*b*cos(C)

Given: a = 850 ft , b = 960 ft ,  C=75°

Solve for c.

c^2=a^2+b^2-2*a*b*cos(C)\\c^2=(850ft)^2+(960ft)^2-2*(850ft)*(960ft)*cos(75)\\\\c=\sqrt{(850ft)^2+(960ft)^2-2*(850ft)*(960ft)*cos(75)\\} \\

c ≈ 1105.308698

c = 1105.31 ft

5 0
2 years ago
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