Answer:
6400
Step-by-step explanation:
its 6400 to the nearest hundred
The algebraic expression for the statement Cindy's age, x, is 3 times her age 6 years ago is 3(x-6).
The given statement is Cindy's age, x, is 3 times her age 6 years ago.
We need to represent the given statement as the algebraic expression.
<h3>What is an algebraic expression?</h3>
In mathematics, an algebraic expression is an expression built up from integer constants, variables, and algebraic operations.
6 years ago Cindy's age(x) is x-6.
3 times Cindy's age=3(x-6)
Therefore, the algebraic expression for the statement Cindy's age, x, is 3 times her age 6 years ago is 3(x-6).
To learn more about the algebraic expression visit:
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<span>copper +copper = copper
0.14x+0.24(100-x) = 0.20*100 = 20</span>
Answer:
Q1
<u>The exponential growth model for frogs:</u>
F- number of frogs, x- number of years, 1.22 - growth factor
<u>Calculations</u>:
- F(5) = 100(1.22)⁵ = 270
- a) F(10) = 100(1.22)¹⁰ = 730
- b) F(20) = 100(1.22)²⁰ = 5335
<em>All numbers rounded </em>
Q2
<u>The exponential growth model for bacteria:</u>
B- number of bacteria, x- number of hours, 1.8 - growth factor
<u>Calculations:</u>
- a) B(5) = 10(1.8)⁵ = 189
- b) B(24) = 10(1.8)²⁴ = 13382588
- c) B(168) = 10(1.8)¹⁶⁸ = 7.68 * 10⁴³
<em>All numbers rounded </em>
Q3.
<u>The exponential growth model for fish:</u>
F- number of fish, x- number of months, 1.02 - growth factor
<u>Calculations:</u>
- a) F(12) = 821(1.02)¹² = 1041
- b) F(120) = 821(1.02)¹²⁰ = 8838
<em>All numbers rounded </em>
Answer: 
Each term is half of the previous one, so the common ratio is 1/2. Then to get from the first term to the nth term, you have to take n - 1 steps, multiplying by 1/2 each time and by 6000 to account for the first term.
i hope this helps! :D
