"Quick question.

Mathematics

2 answers:

givi [52]3 years ago

8 0

Based on the given figure of a plate above, the inner and the outer rims are called CONCENTRIC CIRCLES. By definition, concentric circles are circles having the same or common centers. And in the figure, both the outer and the inner rims have a common center. In addition, the part between two concentric circles of different radii is called an annulus. Hope this is the answer that you are looking for.

Eddi Din [679]3 years ago

6 0

Answer:

Step-by-step explanation:

The answer is concentric circles because the other options just don't make sense. Concentric secants, radius, and chords do not look like that. They have different meanings and also I took a test for FLVS and got it right I did a lesson on how it explains the meanings of each of the terms I just said and it does not match the explanation.

You might be interested in

Which type of proof uses boxes and arrows to show the logical connections between statements?

kramer

A flow proof is the correct answer.

5 0

3 years ago

Read 2 more answers

Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125

liq [111]

For the given equation;

$(3x-5)^2=-125$

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

$\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}$

Now that we have expanded the left side of the equation, we would have;

$\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}$

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}$

ANSWER: