3 years ago

What is the vertex of the parabola given by y = -(x − 2)2 − 1?

1 answer:

5 0

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
y=a(x-{{ h}})^2+{{ k}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
y=-(x-\stackrel{h}{2})^2\stackrel{k}{-1}\qquad \qquad \stackrel{vertex~(h,k)}{(2,-1)}$

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omeli [17]

Answer: The perimeter of the rectangle is 53.8. One side is 24, and the other is 2.9.

Step-by-step explanation:

First you need to divide 69.6 meters by 2.9. This gives you 24 as the other side of the rectangle(remember that the area of a rectangle is $lw$ ). Next you multiply 2.9 x 2. This gives you 5.8, then you multiply 24 by 2. This gives you 48. You add the two values together,and you get the perimeter of the rectangle as 53.8.