1/2*-3 1/2 = -21/4 = -5 1/4= <em>-5.25</em>
I hope this helps!!
D=rt
Divide the t from both sides
D/t=rt/t
The ts on the right will cancel each other out leaving
D/t=r
Since you are looking at the hundreds place, the 9 is in the hundreds place and the number behind it is 8, since this number is greater than 5, the number 9 rounds up so the answer would be 9000.
Answer:
The answer to your question is (fg)(x) = x² - 2; (fg)(0) = -2
Step-by-step explanation:
Data
f(x) = x² + 2x - 1
g(x) = x - 1
(fg)(x) = ?
(fg)(0) = ?
Process
1.- Evaluate f(x) in g(x)
f(g)(x) = (x -1)² + 2(x - 1) - 1
- Simplify
(fg)(x) = x² - 2x + 1 + 2x - 2 - 1
(fg)(x) = x² - 2
2.- Evaluate (fg)(x) when x = 0
(fg)(0) = (0)² - 2
- Simplify
(fg)(0) = 0 - 2
(fg)(0) = -2
The factor of the expression is ![7\left(9y^2+5y+4\right)](https://tex.z-dn.net/?f=7%5Cleft%289y%5E2%2B5y%2B4%5Cright%29)
Explanation:
The given expression is ![63y^2+35y+28](https://tex.z-dn.net/?f=63y%5E2%2B35y%2B28)
We need to determine the factor of the expression.
The factor of the expression can be determined by simplifying the given expression.
Now, we shall rewrite each term as a multiple of 7.
Thus, rewriting, we have,
![63=7\times9](https://tex.z-dn.net/?f=63%3D7%5Ctimes9)
![35=7\times5](https://tex.z-dn.net/?f=35%3D7%5Ctimes5)
![28=7\times4](https://tex.z-dn.net/?f=28%3D7%5Ctimes4)
Hence, substituting these values in the expression, we get,
![(7\times9)y^2+(7\times5)y+(7\times4)](https://tex.z-dn.net/?f=%287%5Ctimes9%29y%5E2%2B%287%5Ctimes5%29y%2B%287%5Ctimes4%29)
Let us factor out the common term 7, we get,
![7\left(9y^2+5y+4\right)](https://tex.z-dn.net/?f=7%5Cleft%289y%5E2%2B5y%2B4%5Cright%29)
Thus, the factor of the expression is ![7\left(9y^2+5y+4\right)](https://tex.z-dn.net/?f=7%5Cleft%289y%5E2%2B5y%2B4%5Cright%29)
The factor of the expression is determined by taking out the common term 7 from the expression.