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Rom4ik [11]
3 years ago
5

Is the following always, sometimes, or never true? 14+3x-7=7x+7-4x a.always b.sometimes c.never

Mathematics
2 answers:
xenn [34]3 years ago
8 0
14+3x-7= 7x+7-4x

Combine like terms
7+3x=3x+7

Since the equations are the same, it is always true.
BaLLatris [955]3 years ago
3 0

Answer:  The correct option is (a) always.

Step-by-step explanation:  We are given to decide whether the following equation is always true, sometimes true or never true :

14+3x-7=7x+7-4x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To check the given equation, we must try to simplify the equation.

From equation (i), we have

14+3x-7=7x+7-4x\\\\\Rightarrow 7+3x=7+3x\\\\\Rightarrow 0=0.

Since the result 0 = 0 is always true, so whatever be the value of x, the given equation is always true.

Option (a) is CORRECT.

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The rectangle has length 8 cm and area 48 cm2.
marishachu [46]

Step-by-step explanation:

Given,

length of rectangle(l)= 8cm

area of rectangle(A) = 48cm2

breadth of rectangle(b) = ?

Perimeter of rectangle (P)=?

We know ,

Area of rectangle(A) = l×b

or, 48cm2 = 8cm×b

or, 48cm2 = 8bcm

or, 48cm2/8cm = b

or, 6cm = b

or, b = 6cm

therefore, b = 6cm

Perimeter of rectangle (P) = 2(l+b)

= 2(8cm+6cm)

= 2×14cm

= 28cm

therefore, Perimeter of rectangle(P) = 28cm

Now,

According to the question,

Perimeter of rectangle(P) = Perimeter of square(P)

So,

Perimeter of square(P) = 28cm

length of square(l) = ?

Area of square (A) = ?

We know,

Perimeter of square (P) = 4l

or, 28cm = 4l

or, 28cm/4 = l

or, 7cm = l

or, l = 7cm

therefore, l = 7cm

Now,

Area of square (A) = l^2

= (7cm)^2

= 7cm×7cm

= 49cm^2

therefore, area of square (A)= 49cm^2

3 0
2 years ago
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Andre45 [30]

Answer:

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Step-by-step explanation:

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