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Nikolay [14]
3 years ago
5

Use factoring to rewrite each expression in n equivalent from. Use the fewest number of terms possible. Show each step of your w

ork
A. 4×+8+2


B. 3×-12+6×+9
Mathematics
1 answer:
goldfiish [28.3K]3 years ago
4 0
A. 4x+10

B. 9x+3

These are the answers to the questions. You just add the like terms together and BAM! You're answer. Hope this helps (:
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The diameter of Saturn at its equator is about 120,540,000 meters. What is 120,540,000 written in word form?
Marianna [84]

Answer:

Step-by-step explanation:

Onehundred twenty-million-fivehundred forty thousand

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A penguin can dive 48 meters below the surface of the water to reach a fish. It dives 2% of the total depth every 1 second.
nikitadnepr [17]
The answer is A- 3.84 meters
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3 years ago
Solve for x: |4x + 12| = 16
JulijaS [17]
4x+12=16
4x=4
x=1

or

-(4x+12)=16
-4x-12=16
-4x=28
x=-7

answer Choice C is correct
6 0
4 years ago
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For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant
nirvana33 [79]

Answer:

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of y with respect to x over the interval by definition of secant line:

r = \frac{y(b) -y(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds of the interval.

y(a), y(b) - Function exaluated at lower and upper bounds of the interval.

If we know that y = 3\cdot x^{2}, a = 3 and b = 6, then the average rate of change of y with respect to x over the interval is:

r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}

r = 27

The average rate of change of y with respect to x over the interval [3,6] is 27.

b) The instantaneous rate of change can be determined by the following definition:

y' =  \lim_{h \to 0}\frac{y(x+h)-y(x)}{h} (2)

Where:

h - Change rate.

y(x), y(x+h) - Function evaluated at x and x+h.

If we know that x = 3 and y = 3\cdot x^{2}, then the instantaneous rate of change of y with respect to x is:

y' =  \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}

y' =  3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}

y' = 3\cdot  \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}

y' = 6\cdot  \lim_{h \to 0} x +3\cdot  \lim_{h \to 0} h

y' = 6\cdot x

y' = 6\cdot (3)

y' = 18

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

5 0
3 years ago
Algebra 2 help ASAP....
zubka84 [21]

Answer:

brainly.com/question/5871139

Step-by-step explanation:

this person explains

8 0
3 years ago
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