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daser333 [38]
3 years ago
15

A technician is launching fireworks near the event of a show. Of the remaining 11 fireworks, 4 are blue and 7 are red. If she la

unches 6 of them what’s the probability that 2 of them will be blue
Mathematics
1 answer:
SpyIntel [72]3 years ago
8 0

\displaystyle |\Omega|=\binom{11}{6}=\dfrac{11!}{6!5!}=\dfrac{7\cdot8\cdot9\cdot10\cdot11}{2\cdot3\cdot4\cdot5}=462\\ |A|=\binom{4}{2}=\dfrac{4!}{2!2!}=\dfrac{3\cdot4}{2}=6\\\\ P(A)=\dfrac{6}{462}=\dfrac{1}{77}\approx1\%

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Peter paid $9.75 to go to the movies, which was $46.25 less than he paid to go to a concert. How much did he pay for the concert
Levart [38]

Answer:

He payed 56 dollars for the concert.

Step-by-step explanation:

46.25 + 9.75= 56

3 0
2 years ago
Suppose a random sample of 50 college students are asked to measure the length of their right foot in centimeters. A 95% confide
hichkok12 [17]

Answer:

A  99% confidence interval  will be wider than a 95% confidence interval

Step-by-step explanation:

From the question we are told that

  The  95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm

Generally the width of a confidence interval is dependent on the margin of error.

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

From the above equation we see that

          E \ \  \alpha \ \   Z_{\frac{\alpha }{2} }

Here  Z_{\frac{\alpha }{2} }  is the critical value of the half of the level of significance and this value  increase as the confidence level increase

Now if a  99% confidence level is  used , it then means that the value of  

 Z_{\frac{\alpha }{2} }  will increase, this in turn will increase  the margin of error and in turn this will increase the width of the confidence interval

Hence a 99% confidence interval  will be wider than a 95% confidence interval

5 0
3 years ago
Plllllllllllllllllleassssssssseeeeeeeeee help
Vlad1618 [11]

Answer:

1/(5^12 * 32^3 * 9^15)

Step-by-step explanation:

5^-12 = 1/(5^12)

32^-3 = 1/(32^3)

9^-15 = 1/(9^15)

1/(5^12) * 1/(32^3) * 1/(9^15) = 1/(5^12 * 32^3 * 9^15)

8 0
2 years ago
Natalie has 500 candy bars to sell for a fundraiser. Let C be the number of candy bars. Let P be the amount made from selling th
Contact [7]

1. Writing p as a function of c gives

P =2c-250

Where C is the number of candy bar

P is the number of candy bar sold.

2. This is expressed as

0 =< C <= 250

3. This is expressed as

0 =< C =< 250

4. Amount made from selling candy bar in the set of interger between 0 to 500

C is given as 500

From the equation P=2C-250

P=2×500-250

P=1000-250 =750.

P=750

5. Amount made selling candy bar for the set of real numbers between 0 and 250

C is equal to 250

From the equation, we have

P=2×250-250

P=500-250 =250.

4 0
2 years ago
Segments UV and WZ are parallel with line ST intersecting both at points Q and R respectively
Zanzabum

The <em><u>correct answer</u></em> is:

Corresponding (for both blanks)

Explanation:

Corresponding angles are angles that are in the same relative position to both the parallel line they are on and the transversal.  In this case, SQU and WRS are both above the parallel line they are on and on the same side of the transversal; this makes them corresponding angles.  This also means it is the corresponding angles postulate.

3 0
3 years ago
Read 2 more answers
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