The function is undefinded if the denominator, x-5, equals 0.
So

.
The domain is

.
In interval notation, this is (-infinity, 5) u (5, infinity).
Answer:
2
Step-by-step explanation:
Write the equation

Add the variables

Multiply 3 x 5

Subtract the parentheses

Subtract the numerator

Reduce the fraction with 3

Reduce the fraction again with 2

And there's your answer of 2!
Answer:
My answer was deleted but it was between 4 and 6 weeks
Step-by-step explanation:
X +x²= 132
x +x²-132= 132-132
x²+x -132 = 0
(x-11) (x+12) = 0
x-11 = 0 X+12=0
x-11+11 = 0+11 X+12-12=0-12
x =11 x= -12
Check
x +x²= 132 x +x²= 132
-12 +-12²= 132 11 +11²= 132
-12 + 144 = 132 11+ 121=132
132= 132 132=132
Since the problem says positive the answer is (11,121)