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3 years ago

54/25 as a terminating decimal

1 answer:

Alex3 years ago

6 0

2.16 <span>Multiply both number by 4. You'll get 216/100. Reduce and you'll have 2.16 Or divide 54 by 25. </span>
<span>Same answer.</span>

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A pound of guinea pig pellets is about 3 cups of food.Each guinea pig eats 1/4 cup is pellets a day. How many days will the pell

kompoz [17]

Answer:

The pellet will last after 12 days

Step-by-step explanation:

* Lets change the story problem to equations to solve it

- There is a pound of guinea pig pellets

- One pound of pellets is about three cups of food

- Each guinea pig eats 1/4 cup of pellets a day

* Lets use these information to solve the problem

∵ One pound of guinea = 3 cups of food

∵ The guinea pig eats 1/4 cup a day

- The pig can finish one cup in four days

∵ The number of days = number of cups ÷ the eaten in a day

∵ The number of cup = 3 cups

∵ The eaten pellets in a day = 1/4

∴ The number of days = 3 ÷ 1/4 = 3 × 4/1 = 12 days

* The pellet will last after 12 days

4 0

3 years ago

Find the surface area of a square pyramid whose base edge is 6cm and whose slant edge is 5cm

dmitriy555 [2]

Check the picture below.

so let's notice, the base is a 6x6 square, and triangular faces have a base of 6 and an altitude/height of 5. So we can just get the area of the square and the triangles and sum them up and that's the area of the pyramid.

$\bf \stackrel{\textit{triangles' area}}{4\left[ \cfrac{1}{2}(6)(5) \right]}+\stackrel{\textit{square's area}}{(6\cdot 6)}\implies 60+36\implies 96$

6 0

3 years ago

Read 2 more answers

Solve for x in the diagram below “x + 54”

vampirchik [111]

Step-by-step explanation:

Um..... Where is the diagram?

8 0

4 years ago

A. A 5in radius ball is in a

abruzzese [7]

Answer:

52.33%

Step-by-step explanation:

Since, all six sides of the box are touching the ball.

So, all the three dimensions of the box are equal.

Hence, it is a cubical box.

Side length of the box (l)

= diameter of the ball

= 2*radius of the ball

= 2*5

= 10 In.

$V_{ball} = \frac{4}{3} \pi r^3$

$V_{ball} = \frac{4}{3} \times 3.14(5)^3$

$V_{ball} = \frac{4}{3} \times 3.14\times 125$

$V_{ball} = \frac{1,570}{3}\: In^3$

$V_{box} =l^3$

$V_{box} =(10)^3$

$V_{box} =1000\: In^3$

Percentage of the space in the box occupied by the ball

$= \frac{V_{ball}}{V_{box} } \times 100$

$= \frac{\frac{1,570}{3}}{1000} \times 100$

$= \frac{1570}{3000} \times 100$

$= \frac{157}{3}$

$= 52.33\%$

5 0

3 years ago

Complete the recursive formula of the arithmetic sequence 8, -5, -18, -31,...

Nady [450]

The formula is taking of 13 each time so the next answers will be -44,-57

6 0

3 years ago

Read 2 more answers