We know that According to Algebra of Real Functions :
If f and g are two real functions which are defined under the same domain then 

Now we need find the Domain of this Function :
The Condition for Square Root to be defined is any Expression under it should be Greater than or Equal to Zero.
When Function is a Fraction, it Cannot be defined when the denominator becomes zero. Because when the denominator is zero, the fraction tends to ∞ (because anything divided by zero tends to ∞)
According to Above Conditions Described above, The Given Function is Definable only when the Expression which is under the Square Root is Greater than Zero and x ≠ 0
⇒ 3x - 9 > 0
⇒ 3x > 9
⇒ x > 3
⇒ The Domain of the Given Function is (3 , ∞)
1st Option is the Answer
<h2>Answer:</h2>
x+10y
<h3>Step-by-step explanation:</h3>
3x+2y+(-2x)+8y
First of all you cannot substitute x with y, so what u do u make the numbers with the same letters they have,and I put -2x because + & - equals to -(minus) :-
3x-2x+2y+8y= x+10y
I don't add 1 to x coze when x alone stands for 1, I added +10y because both the y equations had + they were positive so I add a +.
<h3>Hope it helps </h3>
Answer:
Step-by-step explanation:
5+n+4+7+n+8=360
24+2n=360
2n=360-24
2n=336
n=168
The discriminant is <span>−<span>8
</span></span>f<span>(x)</span>=−3<span>x2</span>−2x−1
is of the form <span><span>a<span>x2</span>+bx+c</span>
</span>,with <span><span>a=−3</span>
</span>, <span><span>b=−2</span>
</span> and <span>c=−<span>1</span></span>
Answer:
no
Step-by-step explanation:
3y+3 doesnt equal 9y+3