Find an equation of the line. Write the equation in the standard form. Through (5,5); parallel to 2x-y=8

1 answer:

6 0

Use point slope form

y - y1 = m(x - x1)
where:-
m = slope of 2x - y = 8 which is 2, x1 = 5 and y1 = 5:-

y - 5 = 2(x - 5)

y - 5 - 2x = -10

y - 2x = -5 <----- Answer

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Given radical a and radical b are in simplest radical form and radical a timed radical b equals c radical d and c radical d is i

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Answer:

See below.

Step-by-step explanation:

Since sqrt(a) and sqrt(b) are in simplest radical form, that means a and b have no perfect square factors. When sqrt(a) and sqrt(b) are multiplied giving c * sqrt(d), the fact that c came out of the root means that there was c^2 inside the product sqrt(ab). This means that a and b have at least one common factor.

ab = c^2d

Example:

Let a = 6 and let b = 10.

sqrt(6) and sqrt(10) are in simplest radical form.

Now we multiply the radicals.

sqrt(a) * sqrt(b) = sqrt(6) * sqrt(10) = sqrt(60) = sqrt(4 * 15) = 2sqrt(15)

We have c = 2 and d = 15.

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Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in

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5 People can be chosen in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

$nCr=\frac{(n)!}{(n-r)!(r)!}$

So here , n =13 and r=5 ,

So after putting the value of n and r , the equation will be

$13C_5=\frac{(13)!}{(13-5)!(5)!}$

$13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}$