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Pachacha [2.7K]
3 years ago
12

¼c+3d when c and d=7​

Mathematics
1 answer:
-Dominant- [34]3 years ago
8 0

Answer:

22.75

Step-by-step explanation:

you substitute the 7 in for c and d. Following PEMDAS, you would then do (1/4) multiplied by 7 and 3 times 7. add those 2 together and you get 22.75 :)

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Maris put trim around a mirror that is the shape of a square. Each side is 24 inches long. Maria has 1 foot of trim left. What w
Dahasolnce [82]

Answer:

16.028 yards

Step-by-step explanation:

1 inch=0.0833333 foot

24 inches=0.0833333×24

=1.9999992 foot

The mirror is square shaped and each side is 24 inches

If each 24 inches=1.9999992 foot

Then,

4 sides of 24 inches=1.9999992×24

=47.9999808 foot

Maria has 1 foot of trim left

Total Length of trim when she started=47.9999808+0.0833333

=48.0833141 foot

=16.02777136667 yards

Approximately,

16.028 yards

8 0
3 years ago
A triangle has two sides of length 15 cm and 17 cm. Select all the values of its third side that would make it a right triangle
Natali [406]

Answer:

\sqrt{514} cm, 8cm, are both options

Step-by-step explanation:

For a right triangle one can find the length of the longest side by using the Pythagorean theorem. So there are two options I can think of that if the triangle is a right triangle will work. First remember what the Pythagorean theorem is : side a^2+side b^2=hypotenuse^2

The hypotenuse is the longest side of a right triangle. So if the sides that are 15 and 17 cm are not the longest sides then the formula would be:

15^{2} +17^2=c^2\\15^2+17^2=\sqrt{514}cm

But if 17cm is the longest side then:

a^2+15^2=17^2\\8^2+15^2=17^2\\a=8cm

Hope this helps!

4 0
3 years ago
Read 2 more answers
Match these similar triangles proof<br>​
AlekseyPX

Answer:

B

C

F

D

H

A

G

E

Step-by-step explanation:

Ok. They are trying to reconstruct the smaller looking triangle in the bigger triangle using angle A as the common angle.

The first statement is always the given.

Second they constructed line segment XY into the bigger triangle so that XY is parallel to BC.

Third, from the construction of the parallel lines we can now find corresponding angles that are congruent. This would be the use of F.

Since we have all three angles in triangle AXY and triangle ABC, then the construction of the smaller triangle we made inside the bigger triangle is similar to the bigger triangle. So we have the triangles are similar. You could say E or D here in my opinion. This is choice D.

Fifth the creation of those fractions of sides being equal comes from us knowing the corresponding sides of similar triangles are proportional. This is choice H.

Things looked cut off for the sixth thing so I can't fully read it, but it is possible a substitution has occured.

The seventh thing is a congruence statement which can be proven by a congruence postulate. The only one listed is SAS. So that is G.

The last thing, since the triangle construction is congruent to the smaller triangle then we know the smaller triangle is also similar to the bigger triangle since the bigger one is also similar to the construction we made. I really think E and D is interchangeable. Choice E goes here.

7 0
3 years ago
You have been hired by joe's gas stop to estimate a demand function for its regular gasoline sales. occordingly, you collect 50
Digiron [165]
(a) Sample correlation ==> -0.7916
(b) Standard Deviation for Quantity ==> 801.6816
(c) Standard Deviation for Price ==> 39.1660
(d) Relation to coefficient on Price ==> <span>−16.2028</span>
8 0
3 years ago
The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}

\dfrac{5}{12} \times 1250

Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}

\dfrac{5}{18} \times 1250^2

∴

Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]

Finally, the standard deviation  of the insurance payment is:

= \sqrt{Var(I(x))}

= 1250 \sqrt{\dfrac{5}{48}}

≅ 404

4 0
3 years ago
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