I bet no body can do it

ch4aika [34]

The GCF of 27 and 18 would be 9. It is the largest or greatest common factor that can be evenly divided by in both the numbers 27 and 18.

7 0

3 years ago

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Original:45 new:30 percent of change

Sveta_85 [38]

Answer:

Explanation:

30-45 = -15

percent of change = 100(-15/45) = -33.33%

6 0

3 years ago

How do I solve f+4/g=6 for f showing my work

V125BC [204]

We have two solutions for this problem based on the given equation.

Answer #1:

If the given equation was:

$f + \frac{4}{g} = 6$

To solve for f, we would need to isolate the "f" on one side of the equation.

In case of the above equation, we can simply do that by subtracting $\frac{4}{g}$ from both sides of the equation

This would give:

f + $\frac{4}{g}$ - $\frac{4}{g}$ = 6 - $\frac{4}{g}$

f = 6 - $\frac{4}{g}$

Answer #2:

If the given equation was:

$\frac{f+4}{g} = 6$

To solve for f, we would still need to isolate the "f" on one side of the equation.

This can be done as follows:

$\frac{f+4}{g} = 6$ ................> multiply both sides by (g)

f + 4 = 6g ................> subtract 4 from both sides of the equation

f + 4 - 4 = 6g - 4

f = 6g - 4

Hope this helps :)

6 0

3 years ago

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Let f(x)=x^2f ( x ) = x 2. Find the Riemann sum for ff on the interval [0,2][ 0 , 2 ], using 4 subintervals of equal width and t

sladkih [1.3K]

Answer:

$A_L=1.75$

Step-by-step explanation:

We are given:

$f(x)=x^2$

$interval = [a,b] = [0,2]$

Since $n = 4$ ⇒ $\Delta x = \frac{b-a}{n} = \frac{2-0}{4}=\frac{1}{2}$

Riemann sum is area under the function given. And it is asked to find Riemann sum for the left endpoint.

$A_L= \sum\limits^{n}_{i=1}\Delta xf(x_i) = \frac{1}{2}(0^2+(\frac{1}{2})^2+1^2+(\frac{3}{2})^2)=\frac{7}{4}=1.75$

Note:

If it will be asked to find right endpoint too,

$A_R=\sum\limits^{n}_{i=1}\Delta xf(x_i) =\frac{1}{2}((\frac{1}{2})^2+1^2+(\frac{3}{2})^2+2^2)=\frac{15}{4}=3.75$

The average of left and right endpoint Riemann sums will give approximate result of the area under $f(x)=x^2$ and it can be compared with the result of integral of the same function in the interval given.

So, $(A_R+A_L)/2 = (1.75+3.75)/2=2.25$

$\int^2_0x^2dx=x^3/3|^2_0=8/3=2.67$

Result are close but not same, since one is approximate and one is exact; however, by increasing sample rates (subintervals), closer result to the exact value can be found.

3 0

3 years ago

A package of four bottles of a sports drink cost $5.28. what is the cost per bottle

Dafna1 [17]

$1.32 per bottle because you would divide $5.28 into 4 and get $1.32

3 0

3 years ago

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