A polynomial function has a zero at 4 (multiplicity 3) and 0 (multiplicity 1)
1 answer:
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Double angle (or half angle, depending how you look at it) identities:
So we have
Note that when taking the square root, we should take into account that that could yield two possible solutions, but we know and
, so it's also the case that
.
Also, the reason we have equality in the last step can be explained like so:
(not unlike the process used to complete the square)
Answer:
5
Step-by-step explanation:
To evaluate (g ￮ h)(9), evaluate h(9) , then use this value to evaluate g(x)
h(9) = = 3, then
g(3) = 2(3) - 1 = 6 - 1 = 5
we have been given that in ΔFGH, the measure of ∠H=90°, GF = 53, HG = 28, and FH = 45. We are asked to find the ratio that represents the sine of ∠G.
First of all, we will draw a right triangle using our given information.
We know that sine relates opposite side of right triangle with hypotenuse.
We can see from the attachment that opposite side to angle G is FH and hypotenuse is GF.
Therefore, the ratio represents the sine of ∠G.
