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romanna [79]
3 years ago
5

A 7.50-g sample of iron is heated in oxygen to form an iron oxide. if 10.71 g of the oxide is formed, what is its empirical form

ula
Chemistry
1 answer:
Zielflug [23.3K]3 years ago
3 0
Answer is: empirical formula is Fe₂O₃.
m(Fe) = 7,50 g.
m(iron oxide) = 10,71 g.
n(Fe) = m(Fe) ÷ M(Fe).
n(Fe) = 7,50 g ÷ 55,85 g/mol = 0,134 mol.
m(O) = m(iron oxide) - m(Fe).
m(O) = 10,71 g - 7,50 g = 3,21 g.
n(O) = 3,21 g ÷ 16 g/mol = 0,20 mol.
n(Fe) : n(O) = 0,134 mol : 0,2 mol = 2 : 3.
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When 0.50 L of a 12 M solution is diluted to 1.0 L, what is the resulting molarity?
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The resulting molarity is 6M.

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If a rock is thrown 0.8 meters into the air, How fast was it thrown
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</span>
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3 years ago
Read 2 more answers
A 254.5 g sample of a white solid is known to be a mixture of KNO3, BaCl2, and NaCl. When 116.5 g of this mixture is dissolved i
Margaret [11]

Answer:

Mass of KNO3 in the original mix is 146.954 g

Explanation:

mass of KNO_3 in original  254.5 mixture.

moles of BaSO_4 = \frac{mass}{Molecular\ Weight}

moles ofBaSO_4  = \frac{68.3}{233.38}

                               = 0.2926 mol of BaSO4

Therefore,

0.2926 mol of BaCl2,

mass of BaCl_2 = mol\times molecular weight

                         = 0.2926\times 208.23

                         = 60.92 g

the AgCl moles = \frac{mass}{Molecular\ Weight}

                          = \frac{199.1}{143.32}

                          = 1.3891 mol of AgCl

note that, the Cl- derive from both, BACl_2 and NaCl

so

mole of Cl- f NaCl = (1.3891) - (0.2926\times 2) = 0.8039 mol of Cl-

mol of NaCl = 0.8039 moles

mass = mol\times Molecular\ Weight  = 0.8039 \times 58 = 46.626\ g \ of \ NaCl

then

KNO3 mass = 254.5 - 60.92-46.626 = 146.954 g of KNO_3

Mass of KNO3 in the original mix is 146.954 g

8 0
3 years ago
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