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Zolol [24]
3 years ago
10

At lunch, the babysitter gives Tanya and Damien each a chocolate candy. Tanya puts her candy on her plate. Damien saves his cand

y in his pocket. After lunch, Damien discovers his candy has melted. Which statement accurately compares the atoms in the two candies?
The atoms in Damien’s candy have less energy.
The atoms in Damien’s candy are vibrating faster.
The atoms in Damien’s candy are unable to move.
Chemistry
1 answer:
evablogger [386]3 years ago
6 0

Answer: B.The atoms ⚛️ in Damien’s candy are vibrating faster ❣️ Yur Welcome

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What is the Lewis structure for Iodide?
jasenka [17]

Answer:

In the Lewis structure for IF5 you'll need to put a total of 12 valence electrons on the Iodine atom in order to draw the Lewis structure. Remember that Iodine (I) can hold more than eight valence electrons. For the IF5 Lewis structure, calculate the total number of valence electrons for the IF5 molecule

Explanation:

<em> I be knowing hope this helps</em>

5 0
2 years ago
For the vaporization reaction Br2(l) → Br2(
oksian1 [2.3K]
    The  temperature  at   which  the  process  be   spontaneous  is  calculated  as  follows

delta  G  =  delta H  -T delta S

let  delta G  be =0

therefore  delta H- T  delta s =0

therefore  T=  delta  H/  delta  S
convert  31   Kj  to  J  =  31  x1000=  31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K


3 0
3 years ago
What is another name for the acid dissociation constant?
sveticcg [70]
A. Ionization constant
4 0
3 years ago
Read 2 more answers
n acid with a pKa of 8.0 is present in a solution with a pH of 6.0. What is the ratio of the protonated to the deprotonated form
Nady [450]

Answer : The ratio of the protonated to the deprotonated form of the acid is, 100

Explanation : Given,

pK_a=8.0

pH = 6.0

To calculate the ratio of the protonated to the deprotonated form of the acid we are using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[Deprotonated]}{[Protonated]}

Now put all the given values in this expression, we get:

6.0=8.0+\log \frac{[Deprotonated]}{[Protonated]}

\frac{[Deprotonated]}{[Protonated]}=0.01  

As per question, the ratio of the protonated to the deprotonated form of the acid will be:

\frac{[Protonated]}{[Deprotonated]}=100  

Therefore, the ratio of the protonated to the deprotonated form of the acid is, 100

5 0
3 years ago
how can knowledge of percent composition help you as a consumer ? how can you promote responsible consumerism ?​
Nonamiya [84]

Answer:

it is a nice question....my mind tells me that the first is it use me as a good vibes and can use to anything the second i will do my best too absorbe it.

Explanation:

Hope this help...

8 0
3 years ago
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