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Bingel [31]
3 years ago
14

A 110.0 ml sample of 0.20 mhf is titrated with 0.10 mcsoh. determine the ph of the solution after the addition of 440.0 ml of cs

oh. the ka of hf is 3.5×10−4.
Chemistry
1 answer:
Margarita [4]3 years ago
6 0
Given:

Concentration of HF = 0.20 m
Volume of HF = 110 ml
Concentration of CsOH = 0.10 m
Volume of CsOH = 440 ml
Ka (HF) = 3.5 x 10^-4

Balanced Chemical Equation:

HF + CsOH ===> CsF + H2O 

pH of the solution = log ([acid]/[base]) + pKa
pH = log ([0.20*(110/1000)]/[0.10*(440/1000)]) - log(3.5x10^-4)
pH = 3.15<span />
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Y= Mx + b
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What is the frequency of an X-ray that has a wavelength of 1.5 x 10 -9 m? The speed of electromagnetic radiation is 3.0 x 10 8 m
AlexFokin [52]

Answer:

2.0x10¹⁷ Hz is the frequency of the X-ray

Explanation:

We can find the frequency of a wave of energy from the wavelenght and its speed using the formula:

v = λƒ

<em>Where v is speed (For electromagnetic radiation = 3.0x10⁸m/s)</em>

<em>λ is the wavelength in meters = 1.5x10⁻⁹m</em>

<em>And f is the frequency in s⁻¹ = Hz</em>

<em />

Replacing:

3.0x10⁸m/s = 1.5x10⁻⁹m*ƒ

3.0x10⁸m/s / 1.5x10⁻⁹m = f

f =

<h3>2.0x10¹⁷ Hz is the frequency of the X-ray</h3>

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3 0
2 years ago
What product is released into Earth's atmosphere through the combustion of<br> fossil fuels?
mezya [45]

Answer:

Carbon Monoxide

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7 0
1 year ago
Indicate which solution in each pair has the lower pH. Your response should be a four letter "word". The first letter should be
JulijaS [17]

Answer:

bcfh

Explanation:

HClO₄ reacts with water thus:

HClO₄ + H₂O → H₃O⁺ + ClO₄⁻

That means HClO₄ produce H₃O⁺ that decreases pH. That means the higher concentration of HClO₄ decreases pH. Thus, lower pH will be:

b) 0.2 M HClO4

The reaction of NaClO₄ is:

NaClO₄ + H₂O → OH⁻ + HClO₄ + Na⁺

The higher concentration of NaClO₄ the higher production of OH⁻ that increase pH, that means the lower concentration of NaClO₄ the lower pH, thus, the answer is:

<em>c) 0.1 M NaClO or</em>

HF reacts with water thus;

HF ⇄ H⁺ + F⁻

The equilibrium constant is:

k = [H⁺] [F⁻] / [HF] = 3,5x10⁻⁴

For HNO₂ equilibrium is:

HNO₂ ⇄ H⁺ + NO₂⁻

k = [H⁺] [NO₂⁻] / [HNO₂] = 4,5x10⁻⁴

As k value is higher for HNO₂, the concentration of H⁺ will be higher in this system doing the HNO₂ with the lower pH.

f) 0.1 M HNO2

NaOH is a strong base that produce OH⁻ that increase pH, pure water is neutral, thus, the lowe pH is:

h) pure water

I hope it helps!

7 0
3 years ago
Sodium chloride is an example of a
Andrei [34K]
C. Weak acid is the correct answer
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3 years ago
Read 2 more answers
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