Answer:
In a bottle.
Explanation:
I would like soda in a bottle because you don't get soda stuck in the aluminum can like you do a bottle. And it's also way more efficient because bottles have caps that you can screw on later, but aluminum doesn't.
Answer:
= 82%
Explanation:
Percentage purity is calculated by the formula;
% purity = (mass of pure chemical/total mass of sample) × 100
In this case;
1 mole of Ca(NO3)2 = 164 g
but; 164 g of Ca(NO3)2 = 40 g Ca
Therefore; mass of Ca(NO3)2 = 164 /40
= 4.1 g
Thus;
% purity of Ca(NO3)2 = (Mass of Ca(NO3)2/ mass of the sample)× 100
= (4.1 g/ 5 g) × 100
= 82%
Answer:
Amount of sucrose required = 278.85 g
Explanation:
(w/v)% = 39.0 %
Volume of the solution = 715 mL
39% (w/v) means 39 g of sucrose present in 100 mL of the solution.
Using unitary method,
For making 39% solution,
100 mL solution requires 39 g of the sucrose
therefore, 715 mL solution requires:
= 278.85 g
18 percent of x will be equal to 12 percent of y
Answer:
Option D. Al is above H on the activity series.
Explanation:
The equation for the reaction is given below:
2Al + 6HBr —> 2AlBr₃ + 3H₂
The activity series gives us a background understanding of the reactivity of elements i.e how elements displace other elements when present in solution.
From the activity series of metals, we understood that metal higher in the series will displace those lower in the series.
Considering the equation given above, Al is higher than H in the activity series. Thus, the reaction will proceed as illustrated by the equation.
Therefore, we can conclude that the reaction will only occur if Al is higher than H in the activity series.