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horrorfan [7]
3 years ago
5

A certain substance makes up 4.8 × 10–4 percent by mass of a normal healthy human being. How many grams of that substance would

be found in the body of a person weighing 120 lb? (1.0 kg = 2.2 lb).
Chemistry
1 answer:
iris [78.8K]3 years ago
4 0

Answer:

0.2615 g

Explanation:

Given that mass of the body = 120 lb

The conversion of lb to g is shown below as:-

1 lb = 454 g

So, 120 lb = 120*454 g = 54480 g

The substance is 4.8\times 10^{-4}\ \% of the human body

So, Mass of that substance in the body of mass 54480 g is:-

m=\frac{4.8\times 10^{-4}}{100}\times 54480\ g=0.2615\ g

<u>0.2615 g of that substance would be found in the body of a person weighing 120 lb.</u>

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How many moles of CaCl2 are contained in 0.448 L of a 0.85 M CaCl2 solution?
kati45 [8]

Answer:

0.3808

Explanation:

number of moles,n=Conc.XVol.

hence 0.85X0.448

3 0
3 years ago
For the following reaction, 38.3 grams of sulfuric acid are allowed to react with 33.5 grams of calcium hydroxide sulfuric acid(
Likurg_2 [28]

Answer:

What is the maximum amount of calcium sulfate that can be formed? 53.1 grams CaSO4

What is the FORMULA for the limiting reagent? H2SO4

What amount of the excess reagent remains after the reaction is complete? 4.59 grams of Ca(OH)2

Explanation:

Step 1: Data given

Mass of sulfuric acid = 38.3 grams

Molar mass of H2SO4 = 98.08 g/mol

Mass of calcium hydroxide = 33.5 grams

Molar mass of Ca(OH)2 = 74.09 g/mol

Step 2: The balanced equation

H2SO4 + Ca(OH)2 → CaSO4 + 2H2O

Step 3: Calculate moles of H2SO4

moles H2SO4 = mass H2SO4 / molar mass H2SO4

moles H2SO4 = 38.3 grams / 98.08 g/mol

moles H2SO4 = 0.390 moles

Step 4: Calculate moles of Ca(OH)2

moles Ca(OH)2 = 33.5 grams / 74.09 g/mol

moles Ca(OH)2 =0.452 moles

Step 5: Calculate limiting reactant

For 1 mol H2SO4, we need 1 mol of Ca(OH)2 to produce, 1 mol of CaSO4 and 2 mol of H2O

H2SO4 is the limiting reactant. It will completely be consumed (0.390 moles).

Ca(OH)2 is in excess. There will be consumed 0.390 moles

There will remain 0.452 - 0.390 = 0.062 moles

This is 0.062 * 74.09 g/mol = 4.59 grams

Step 6: Calculate moles of calcium sulfate

For 1 mol H2SO4, we need 1 mol of Ca(OH)2 to produce, 1 mol of CaSO4 and 2 mol of H2O

For 0.390 moles of H2SO4, there will be produced 0.390 moles of CaSO4

Step 7: Calculate mass of CaSO4

Mass CaSO4 = moles CaSO4 * molar mass CaSO4

Mass CaSO4 = 0.390 moles * 136.14 g/mol

Mass of CaSO4 = 53.1 grams

7 0
3 years ago
Is the sky a solid,liquid,or gas
DochEvi [55]
The air in the sky and the clouds are gas, however some things in the sky [such as the sun/moon] are solid.
Hope that helped!
5 0
3 years ago
Explain how to use a graph to show whether or not the speed of an object is constant.
Sonbull [250]

Answer:

A horizontal line on a speed-time graph represents a constant speed. A sloping line on a speed-time graph represents an acceleration. The sloping line shows that the speed of the object is changing. The object is either speeding up or slowing down.

3 0
3 years ago
Given a 0.200 M solution of anserine at its isoelectric point and ready access to 0.100 M HCl, 0.100 M NaOH and distilled water,
vekshin1

Solution :

Given :

Amount of anserine solution = 0.200 M

pH value is = 7.20

Preparation of 0.04 M solution of anserine from the 0.2 M solution.

0.2 M x x = 0.04 M x 1000 ml

x = 200 ml

So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.

0.1 M x x = 0.04 x 1000 ml

x = 400 ml

Therefore, 400 ml of HCl is needed.

6 0
3 years ago
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