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horrorfan [7]
3 years ago
5

A certain substance makes up 4.8 × 10–4 percent by mass of a normal healthy human being. How many grams of that substance would

be found in the body of a person weighing 120 lb? (1.0 kg = 2.2 lb).
Chemistry
1 answer:
iris [78.8K]3 years ago
4 0

Answer:

0.2615 g

Explanation:

Given that mass of the body = 120 lb

The conversion of lb to g is shown below as:-

1 lb = 454 g

So, 120 lb = 120*454 g = 54480 g

The substance is 4.8\times 10^{-4}\ \% of the human body

So, Mass of that substance in the body of mass 54480 g is:-

m=\frac{4.8\times 10^{-4}}{100}\times 54480\ g=0.2615\ g

<u>0.2615 g of that substance would be found in the body of a person weighing 120 lb.</u>

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Answer:

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Explanation:

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See an example:

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      This equation is not balanced: the  number of atoms of oxygenin the reactant side is 2 while the number of atoms of oxygen isn the product side is 1. In order to balance the equation you need to add some coefficients.

When no coefficients are shown it is understood that the coefficient is 1.

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The coefficients 2 in front of H₂ and 1 (understood) in front of O₂, in the reactant side, and 2 in front of H₂O, in the product side, balance the equation.

Those coefficients mean that the 2 molecules (or mole of molecules) of H₂ react with 1 molecule (or mole of molecules) of O₂ to form 2 molecules (or moles) of H₂O (product side).

That is the mole ratio: 2 H₂ : 1 O₂ : 2 H₂O.

Notice that, in spite of the aboslute numbers may change, the mole ratio is unique for any chemical reaction.  For example 4 : 2 : 4 is the same ratio that 2 : 1 : 2, or 8 : 4 : 8, but the most common practice is to use the most simple form of the ratio, i.e. 2: 1: 2.

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