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Stolb23 [73]
3 years ago
12

Identify each substance as an acid or a base.

Chemistry
2 answers:
Anika [276]3 years ago
7 0

Answer:

Explanation:

To determine whether a substance is an acid or a base, count the hydrogens on each substance before and after the reaction. If the number of hydrogens has decreased that substance is the acid (donates hydrogen ions). If the number of hydrogens has increased that substance is the base (accepts hydrogen ions).

svp [43]3 years ago
4 0

Explanation:

<u>The first one is a base</u>

<u>The second one is an acid</u>

A base has a pH above 7

An acid has a pH below 7

Hope I helped!!! Have a great day!

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The decomposition of hydrogen peroxide (H2O2(aq)) is proposed to follow a reaction mechanism of: Step 1: H2O2(aq) + Br–(aq)→H2O(
lys-0071 [83]

Answer:

Option (1) Br– is the catalyst, and the reaction follows a faster pathway with Br– than without

Explanation:

Let us consider the equation below:

Step 1:

H2O2(aq) + Br–(aq) → H2O(l) + BrO–(aq)

Step 2:

BrO–(aq) + H2O2(aq) → H2O(l) + O2(g) + Br–(aq)

From the above equation, we can see that Br– is unchanged.

This implies that Br– is the catalyst as catalyst does not take part in a chemical reaction but they create an alternate pathway to lower the activation energy in order for the reaction to proceed at a much faster rate to arrive at the products.

8 0
2 years ago
Which set of numbers gives the correct possible values of I for n = 22
Alexandra [31]

Answer:

Hello friends

Explanation:

<h3>For a given principal quantum number for or n, the corresponding angular quantum number or is equivalent to a range between 0 and( n-1)</h3>

<h3>This means that the angular quantum number for a principal quantum number of 2 is equivalent to.</h3>

<h3>1 = 0 - > (n - 1) = 0 - > (2 - 1) = 0 - > 1</h3>

<h3>Hope it's helpfully. </h3>
4 0
2 years ago
All of the Gathered in an investigation must be recorded. (Fill in the blank)
Zigmanuir [339]
The answer is "Incidents"
4 0
3 years ago
A pump contains 0.5 L of air at 203kPa. You draw back on the piston of the pump until the pressure reads 25.4kPa. What is the vo
densk [106]
<h3><u> Answer</u>;</h3>

= 4.0 L

<h3><u>Explanation;</u></h3>

Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to pressure at a constant temperature.

Therefore; <em>Volume α 1/pressure</em>

<em>Mathematically; V α 1/P</em>

<em>V = kP, where k is a constant;</em>

<em>P1V1 = P2V2</em>

<em>V1 = 0.5 l, P1 =203 kPa, P2 = 25.4 kPa</em>

<em>V2 = (0.5 × 203 )/25.4 </em>

<em>     = 3.996 </em>

<em>    ≈ </em><em><u>4.0 L</u></em>

6 0
2 years ago
purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode
stiv31 [10]

The chromium in the electrolytic solution is present as cr³⁺ will take 6.19 hours  will it take to plate 18.0 kg of chromium onto the cathode if the current passed through the cell is held constant at 45.0 A.

It is given that mass is 18 kg. Converting mass into grams

18 x (1000g / 1 kg)

= 18000 g

So, 18 kg = 18000 g

Now, calculate the number of moles

No. of moles = mass of Cr / molecular mass of Cr

No. of moles = 18000 / 52 g/mole

No. of moles = 346.15 mole

For , Cr³⁺, 3 moles of electrons are required

Hence,

3 x 346.15 mole

1038.45

As 96500 C of charge are present in 1 mole of electrons. As a result, the charge held by 1038.45 mole of electrons will be determined as follows.

= 1038.45mol x  96500 C / mole

= 10.02 x 10⁷ C

As, we know that relation between charge, current and time is as follows.

Q = I x T

Current is given as 45 A

Therefore, charge is calculated  

T = Q / I

T = 100.21 x 10⁶ / 45

T = 2.227 x 10⁶

As there are 3600 seconds in one 1 hour. Converting 2.227 x 10⁶ into hours are

= 2.227 x 10⁶ / 3600 sec/h

= 6.19 hours

Thus, if the current flowing through the cell is maintained constant at 45 A, we may estimate that it will take 6.19 hours to plate 18 kg of chromium onto the cathode.

To know more about  electrolytic solution visit :

brainly.com/question/9203208

#SPJ4

4 0
1 year ago
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