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scZoUnD [109]
3 years ago
7

The ratio of a model building's dimensions to the building's actual dimensions is 1/52. If the height of the model is 15 inches,

what is the height of the actual building in feet?
Mathematics
1 answer:
g100num [7]3 years ago
4 0
Set this up as a proportion with the model stuff on top and actual building stuff on bottom.  \frac{1}{52} = \frac{15}{x}.  Cross multiply to get x = 780.  The actual building is 780 inches.  In feet that is 65.
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2. The following formula relates three quantities: Force (F), mass (m), and acceleration (a).
castortr0y [4]

Let

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m--------> represent the mass

a-------> represent the acceleration

we know that

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F=ma

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Divide both sides by the mass

a=\frac{F}{m}

therefore

<u>the answer part a) is equal to</u>

a=\frac{F}{m}

<u>Part b) </u>Let the force be 25 units and the mass be m = 10 units. What is the acceleration, a?

we know that

the formula of acceleration is equal to

a=\frac{F}{m}

in this problem

we have

F=25\\m=10

Substitute the values n the formula

a=\frac{25}{10}

a=2.5

therefore

<u>the answer part b( is equal to</u>

a=2.5

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F=ma

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m=\frac{F}{a}

in this problem

we have

F=25\\a=5

Substitute the values n the formula

m=\frac{25}{5}

m=5

therefore

<u>the answer Part c) is </u>

m=5

5 0
3 years ago
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Sonja [21]

Answer:

(5, - 4 )

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3x - y = 19 → (2)

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9x - 3y = 57 → (3)

Add (1) and (3) term by term to eliminate y

(2x + 9x) + (3y - 3y) = (- 2 + 57), that is

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x = 5

Substitute x = 5 into either of the 2 equations and solve for y

Substituting into (1)

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10 + 3y = - 2 ( subtract 10 from both sides )

3y = - 12 ( divide both sides by 3 )

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8 0
3 years ago
I need help with this math question ​
Mandarinka [93]

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Step-by-step explanation:

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