Answer:
The percent of the area under the density curve where
is more that 3 is 25 %.
Step-by-step explanation:
Since the density curve is a linear function, the area under the curve can be calculated by the geometric formula for a triangle, defined by the following expression:
(1)
Where:
- Area, in square units.
- Base of the triangle, in units.
- Height of the triangle, in units.
The percent of the area is the ratio of triangle areas under the density curve multiplied by 100 per cent, that is:
![x = \frac{\frac{1}{2}\cdot (5-3)\cdot (0.25) }{\frac{1}{2}\cdot (5-1)\cdot (0.5) }\times 100\,\%](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%285-3%29%5Ccdot%20%280.25%29%20%7D%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%285-1%29%5Ccdot%20%280.5%29%20%7D%5Ctimes%20100%5C%2C%5C%25)
![x = 25\,\%](https://tex.z-dn.net/?f=x%20%3D%2025%5C%2C%5C%25)
The percent of the area under the density curve where
is more that 3 is 25 %.
Answer: ![50x+100\geq18,000](https://tex.z-dn.net/?f=50x%2B100%5Cgeq18%2C000)
Step-by-step explanation:
Let w denotes a seven letter word which Sal will need to make to break the record.
Since you get 50 points for each seven-letter and 100 points for playing the game.
Then the total points earned by you by making w seven letters words will be:
![50x+100](https://tex.z-dn.net/?f=50x%2B100)
Since, Sal wants to break that record, and needs 18,000 points or more to do so.
Then , the required inequality will be :
![50x+100\geq18,000](https://tex.z-dn.net/?f=50x%2B100%5Cgeq18%2C000)
The answer to this is 14. To find the hypotenuse from the short do 2S, and for Short to Long it is S Root 3.
Hope this helped! Please Mark as Brainliest!
There are 2 ways to turn a number into a percent...
(1) move the decimal 2 spaces to the right....0.3 = 30%
(2) multiply by 100....0.3 x 100 = 30%
Since you did not attach any picture we cannot say for sure what is the correct answer, but we can discuss the options in order to find the most probable correct answer.
First of all, according to the Cavalieri's principle, an oblique cylinder has the same volume as a right cylinder with the same base surface area and same height.
A cross-section of an oblique cylinder will be a small right cylinder with the same base surface area and a height as small as possible.
I guess the oblique cylinder has height h and it is divided into many (probably 10) cross-sections.
Option A: <span>πr2h
This is exactly the volume of the right cylinder, therefore, unless you are given a cross-section of height h (which would be too easy), this won't be the correct answer.
Option B: </span><span>4πr2h
This is 4 times the right cylinder. Again, here the height of the cross-section should</span> be 4h, but it doesn't sound like a possible data (too easy again).
Option C: <span>1 10 πr2h
Here comes a n issue with the notation: I think the right number you meant to write is (1/10)</span>·πr2h and not 110·<span>πr2h.
If I am right, this means that your oblique cylinder of height h is divided into 10 cross-sections, and therefore the volume of each of these cross-sections will be a tenth of the volume of the oblique cylinder, which means </span>1/10·<span>πr2h.
Option D: </span><span>1 2 πr2h
Here, we have the same notation issue as before. I think you meant (1/2)</span>·<span>πr2h.
Here, your oblique cylinder height h should be divided into only 2 cross-sections. Now, we said the cross-section's height should be the smallest as possible, so an oblique cylinder divided only into two pieces doesn't sound good.
Therefore, the most probable correct answer will be C) </span>(1/10)·<span>πr2h</span>