The given values are:
p = 22% = 0.22
Zc = 1.645 at 90% confidence level.
margin of error, E = 0.04
The formula we can use here is:
E = sqrt(pq/n) * Zc
0.04 = sqrt(0.22*(1-0.22)/n)*1.645
n = (0.22*(1-0.22))*(1.645/0.04)^2
n = 290.22
hence minimum sample size = 290
The correct answer for the question shown above is: Gabriel should use 2 kilograms of compost.
The explanation is shown below:
1. To solve the exercise you must apply the following proccedure:
2. You have that He
wants it to be 2 parts compost to 10 parts potting soil and he
wants to end up with 10 grams of mix. Therefore:
=(2/12)x12 kilograms
=0.166x12 kilograms
=2 kilograms
I’m pretty sure it would be just E and F
15,000 --> fifteen thousand
400 --> four hundred
00 --> zero
9 --> nine
If you put this all together it gives you fifteen thousand four hundred and nine.
Do you still need help with it I can help you?
