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jasenka [17]
3 years ago
5

I NEED HELP ASAP!!!

Mathematics
1 answer:
Andre45 [30]3 years ago
4 0

Answer:

48 cubic centimeters

Step-by-step explanation:

First you multiply the with times the length

2 times 24 yay

and there answer! :3

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Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
2 years ago
What is the answer to the question
vazorg [7]
The answer would be B. <span>linear pair theorem</span>
8 0
3 years ago
If you bought a stock last year for a price of $67, and it has risen 12% since then, how much is the stock worth now, to the nea
lisabon 2012 [21]

Answer:$75.04

Step-by-step explanation:

last year price=$67

12% of 67

12/100 x 67

(12 x 67) ➗ 100

804 ➗ 100=8.04

Since it has risen by 12%

There new price is 67+8.04=75.04

4 0
3 years ago
This month salesperson A made 11% of $67,530.Salesperson B made 8% of $85,750.Who made more commission this month?How much did t
katovenus [111]
The answer is salesperson b
7 0
3 years ago
Read 2 more answers
F(x)=4x+1 and g(x)=x^2-5find(f-g)(x)
Vinvika [58]

Answer:

<h2>-x²+4x +6</h2>

Step-by-step explanation:

Given f(x)=4x+1 and g(x)=x²-5

(f-g)(x) is derived by taking the difference of both functions

(f-g)(x) = f(x)-g(x)

(f-g)(x) = 4x+1 - (x²-5)

(f-g)(x)  = 4x+1-x²+5

(f-g)(x)  = -x²+4x +6

This gives the requires expression

4 0
3 years ago
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