Answer:
<u>For one Necklace you would need...</u>
24 blue beads.
16 white beads.
4 green beads.
Ratio: 24: 16: 4
Step-by-step explanation:
If you quadruple the amount of beads from the original amount (6 : 4: 1), the total beads for that necklace will be 44.
Step 1: 6 x 4 = 24 (amount of blue beads in necklace).
Step 2: 4 x 4 = 16 (amount of white beads in necklace).
Step 3: 1 x 4 = 4 (amount of green beads in necklace).
Now check to see if the total of all types of beads sum up to 44:
Step 4: 24 + 16 + 4 = 44
______________-
There is your answer:
You need 24 blue beads, 16 white beads, and 4 green beads to have a total sum of 44 beads in that one necklace.
-2x+3=15
Subtract 3 from both sides:
-2x=12
Divide -2 from both sides:
X=-16 is your answer
Answer:
L.H.S.
= (cos5a.sin2a-cos4a.sin3a)/ (sin5a.sin2a-cos4a.cos3a)
Multiply numerator and denominator by 2.
= 2(cos5a.sin2a - cos4a.sin3a) / 2(sin5a.sin2a - cos4a.cos3a)
= (2cos5a.sin2a - 2cos4a.sin3a)/
(2sin5a.sin2a - 2cos4a.cos3a) = [sin(5a+2a)-sin(5a-2a)-sin(4a+3a)
+sin(4a-3a)]/[cos(5a-2a)-cos(5a+2a)-sin(4a-3a) +cos(4a+3a)]
= (sina - sin3a)/(cso3a-cosa)
= (-2cos2a.sina)/(-2sin2a.sina)
= cos2a/sin2a
= cot2a
= R.H.S.
Answer:
if Im not mistaken it is 2
Step-by-step explanation:
2! Is the same thing as 2*1 and 2*1 is 2, so technically for factorials the higher in number you get you have to multiply all the numbers going back to one