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Angelina_Jolie [31]
3 years ago
8

Hello everyone (this is 6th grade math)​

Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0

Answer:

7 batches

Step-by-step explanation:

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3.3.1. Calculate the new cost per night of the standard and family standard chalets. Round of (4) your answer to the nearest hun
Taya2010 [7]
  • The information to complete the table is given below:
  • Equation that shows the relationship between the cost per night C and the number of people staying in the chalet n:                              C=  4000-100(n-1)

<h3>What is Equation?</h3>

An equation is a mathematical expression that contains an equals symbol. Equations often contain algebra. Algebra is used in math when you do not know the exact number in a calculation.

Given that:

Pules Rs 4000 per night but will decrease the amount by R100 per person occupying the chalet.

Number of People          Cost per night

          1                                       4000

          2                                       3900

          3                                      3800

          4                                       3700

          5                                       3600

          6                                       3500

          7                                       3400

          8                                       3300

          9                                       3200

          10                                      3100

let C be cost per night and n be the number of people of staying in chalet.

equation:   C=  4000-100(n-1)

      for n=1: C= 4000- 0=4000

            n=2, C= 4000-100(1)= 3900

The graph is attached below:

Learn more about equation here:

brainly.com/question/10413253

#SPJ1

     

5 0
2 years ago
What is the approximation of pi to the nearest hundredth ?
saveliy_v [14]

Answer:

3.14

That is the value of pi to the second decimal point

7 0
3 years ago
Solve the equation with quadratic formula
Alla [95]

Answer:

x=4+9i,:x=4-9i

Step-by-step explanation:

put it into the quadratic formula

x=-(b+/- sqr b^2-4ac)/2a

8+/- sqr 64-97/2

7 0
3 years ago
Read 2 more answers
Rewrite the equation A = 1 2 ( b 1 + b 2 ) h A = 1 2 b 1 + b 2 h to show the expression that can be used to find the value of h.
Wittaler [7]
H=2A/b1+b2. Hope this helps!!

5 0
3 years ago
At time t=0 sec, a tank contains 15 oz of salt dissolved in 50 gallons of water. Then brine containing 88oz of salt per gallon o
maria [59]

Answer:

a) s(t) =400- 385 e^{-\frac{1}{10} t}

b) s(t=25min) =400- 385 e^{-\frac{1}{10}25}=368.397

Step-by-step explanation:

Part a

Assuming that the original concentration of salt is 8 oz/gal and that the rate of in is equal to the rate out = 5 gal/min.

For this case we know that the rate of change can be expressed on this way:

Rate change = In-Out

And we can name the rate of change as \frac{ds}{dt}=rate change

And our variable s would represent the amount of salt for any time t.

We know that the brine containing 8oz/gal and the rate in is equal to 5 gal/min and this value is equal to the rate out.

For the concentration out we can assume that is \frac{s}{50gal}

And now we can find the expression for the amount of salt after time t like this:

\frac{dS}{dt}= 8 \frac{oz}{gal}(5\frac{gal}{min}) -\frac{s}{50gal} 5 \frac{gal}{min} =40\frac{oz}{min}- \frac{s}{10} \frac{oz}{min}

And we have this differential equation:

\frac{dS}{dt} +\frac{1}{10} s = 40

With the initial conditions y(0)=15 oz

As we can see we have a linear differential equation so in order to solve it we need to find first the integrating factor given by:

\mu = e^{\int \frac{1}{10} dt }= e^{\frac{1}{10} t}

And then in order to solve the differential equation we need to multiply with the integrating factor like this:

e^{\frac{1}{10} t} s = \int 40 e^{\frac{1}{10} t} dt

e^{\frac{1}{10} t} s = 400 e^{\frac{1}{10} t} +C

Now we can divide both sides by e^{\frac{1}{25} t} and we got:

s(t) =400 + C e^{-\frac{1}{10} t}

Now we can apply the initial condition in order to solve for the constant C like this:

15 = 400+C

C=-385

And then our function would be given by:

s(t) =400- 385 e^{-\frac{1}{10} t}

Part b

For this case we just need to replace t =25 and see what we got for the value of the concentration:

s(t=25min) =400- 385 e^{-\frac{1}{10}25}=368.397

7 0
3 years ago
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