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Bogdan [553]
3 years ago
9

I don't understand how to do this number line problem. I need help

Mathematics
2 answers:
storchak [24]3 years ago
6 0
Negative numbers go below 0 on a number line and positives go above 0 for example - 2/3 will go below and 0 will go on 0 and 5/3 will go over 0.
Hope that helps!!!
Crank3 years ago
3 0
The 3rd number line, (the one farthest to the right) is the line graph that shows the locations required.

If you need me to explain, just let me know!
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If ABCD is an A4 sheet and BCPO is the square, prove that △OCD is an isosceles triangle. And find the angles marked as 1 to 8 wi
Dmitry [639]

Answer:

The diagram for the question is missing, but I found an appropriate diagram fo the question:

Proof:

since OC = CD = 297mm Therefore, Δ OCD is an isoscless triangle

∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

∠DOP = 22.5°

∠PDO = 67.5°

∠ADO = 22.5°

∠AOD = 67.5°

Step-by-step explanation:

Given:

AB = CD = 297 mm

AD = BC = 210 mm

BCPO is a square

∴ BC = OP = CP = OB = 210mm

Solving for OC

OCB is a right anlgled triangle

using Pythagoras theorem

(Hypotenuse)² = Sum of square of the other two sides

(OC)² = (OB)² + (BC)²

(OC)² = 210² + 210²

(OC)² = 44100 + 44100

OC = √(88200

OC = 296.98 = 297

OC = 297mm

An isosceless tringle is a triangle that has two equal sides

Therefore for △OCD

CD = OC = 297mm; Hence, △OCD is an isosceless triangle.

The marked angles are not given in the diagram, but I am assuming it is all the angles other than the 90° angles

Since BC = OB = 210mm

∠BCO = ∠BOC

since sum of angles in a triangle = 180°

∠BCO + ∠BOC + 90 = 180

(∠BCO + ∠BOC) = 180 - 90

(∠BCO + ∠BOC) = 90°

since ∠BCO = ∠BOC

∴  ∠BCO = ∠BOC = 90/2 = 45

∴ ∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

For ΔOPD

Tan\ \theta = \frac{opposite}{adjacent}\\ Tan\ (\angle DOP) = \frac{87}{210} \\(\angle DOP) = Tan^-1(0.414)\\(\angle DOP) = 22.5 ^{\circ}

Note that DP = 297 - 210 = 87mm

∠PDO + ∠DOP + 90 = 180

∠PDO + 22.5 + 90 = 180

∠PDO = 180 - 90 - 22.5

∠PDO = 67.5°

∠ADO = 22.5° (alternate to ∠DOP)

∠AOD = 67.5° (Alternate to ∠PDO)

3 0
3 years ago
How to divided 245 by 70 <br> Show your work
Bas_tet [7]

Answer:

Step-by-step explanation:

Hello!

          2          4              5          ∟ 70

        -2           1                                 3, 5

------------------------

                      3              5        0

                      3              5       0

                -   --------------------------------

                     0                0        0

6 0
2 years ago
Complete the square to rewrite x^2+y^2+2x+6y-6=0 in graphing form
Ksivusya [100]

Answer:

(x + 1)² + (y + 3)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² + 2x + 6y - 6 = 0

Collect the x and y terms together and add 6 to both sides

x² + 2x + y² + 6y = 6

To complete the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(3)y + 9 = 6 + 1 + 9

(x + 1)² + (y + 3)² = 16

with centre = (- 1, - 3) and r = \sqrt{16} = 4

4 0
3 years ago
If the check after the substitution of the answer doesn't work, does that mean that the result is incorrect for equation with va
Alecsey [184]
I don't understand what your point is. Mind posting a picture or something?
8 0
3 years ago
What is the union of the set (1, 4, 6, 8 1/2,10) and (1, 3, 11/2, 6, 10 1/2)
makkiz [27]

Answer:

(1, 4, 6, 8, \frac{1}{2}, 10, 3, \frac{11}{2})

Step-by-step explanation:

We need to find union of given sets (1, 4, 6, \frac{1}{2}, 10) and (1, 3, \frac{11}{2}, 10, \frac{1}{2})

We know by definition that union of two given sets say A and B is set C with all the unique and common values given in set A and B.

∴ (1, 4, 6, \frac{1}{2}, 10) ∪ (1, 3, \frac{11}{2}, 10, \frac{1}{2}) = (1, 4, 6, 8, \frac{1}{2}, 10, 3, \frac{11}{2})

4 0
3 years ago
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