Substitute x for 7.
f(x)=22x+12
f(7)=22(7)+12
Multiply first, then complete addition.
f(7)=154+12
f(7)=166
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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I think it's the third one too
Well you need to find a common denominator which 30 is the closest one. 5/6 becomes 25/30, 9/10 becomes 27/30. 27/30+ 25/30 = 52/30. To simplify that you divide by 2 to get 26/15. It is no longer divisible to a whole number after that point.
-1/3(px-2) = 9
ok! so first we want to isolate x.
multiply both sides by -3/1 (this is the reciprocal of -1/3)
(px-2) = -27
px = -27 + 2
px = -25
x = -25/p
hope this helped!
