Question

Can somebody help me with the Math's questions on Pythagoras Theorem? Thanks

Answer 1

Answer:

Part a) $AB=17\ m$

Part b) $AC=20.8\ m$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Part a) Find the length AB

Applying the Pythagoras Theorem in the right triangle ABH

$AB^2=AH^2+HB^2$

where

AB is the hypotenuse (the greater side)

AH and HB are the legs of the right triangle

we have

$AH=FG=8\ m$

$HB=GB-ED=26-11=15\ m$

substitute the values

$AB^2=8^2+15^2$

$AB^2=289$

$AB=17\ m$

Part a) Find the length AC

Applying the Pythagoras Theorem in the right triangle ABC

$AC^2=AB^2+BC^2$

where

AC is the hypotenuse (the greater side)

AB and BC are the legs of the right triangle

we have

$BC=12\ m$

$AB=17\ m$

substitute

$AC^2=17^2+12^2$

$AC^2=433$

$AC=20.8\ m$