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3 years ago

15

Derive the following equations for uniformly accelerated motion by graphical method. a) Velocity -time relation b) Position - ti

me relation 3) Position – velocity relation.

1 answer:

LUCKY_DIMON [66]3 years ago

4 0

Answer:

a) velocity - time realation

that graph's gradient gives the uniform acceleration

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To show that displacement current is necessary to make Ampère's law consistent for a charging capacitor Ampère's law relates the

ella [17]

Answer: The Ampère -Max-well law

Explanation:

The Ampère -Max-well law relates magnetic flux and electric current. It determines the relationship between current in association with a magnetic field and also magnetic field in association to related current.

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3 years ago

14 What is the weight of each of

Gwar [14]

Explanation:

On earth,

g=10 m/s^2

When M=2 kg,

weight on earth=2×10

=20N

When M=3.5 kg,

weight on Earth=3.5×10

=35N

When M=5kg,

weight on Earth=5.25×10

=52.5N

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3 years ago

Kyle lays a mirror flat on the floor and aims a laser at the mirror. The laser beam reflects off the mirror and strikes an adjac

Elena L [17]

Answer:

The angle of incidence is $\theta_i =42.6^o$

Explanation:

The diagram for this question is shown on the first uploaded image

From the question we are told that

The distance between the mirror and the wall is $a = 33.7 cm$

The height of the above the mirror is $b = 36.7 cm$

Generally the angle which the reflected ray make with the mirror is mathematically evaluated as

$\alpha =tan ^{-1} (\frac{b}{a})$

substituting values

$\alpha = tan ^{-1}( \frac{36.7}{33.7})$

$\alpha =47.4^o$

From the diagram we can deduce that the angle of incidence is

$\theta_i = 90 - \alpha$

So $\theta_i = 90 - 47.4$

$\theta_i =42.6^o$

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3 years ago

A slender rod is 80.0 cm long and has mass 0.120 kg. A small 0.0200-kg sphere is welded to one end of the rod, and a small 0.050

BartSMP [9]

Answer:

Explanation:

Given that,

Slender rod

Length of rod=80cm=0.8m

Mass of slender rod=0.12kg

Sphere Bob at one end

Mass M1=0.02kg

Sphere Bod at the other end

Mass M2 =0.05kg

Linear speed of mass 2 at the lowest point

We need to calculate the change in potential of the complete system. m2 and m3 are the masses at the rod ends. note the rod centre of mass neither gains nor loses potential.

So, at the lowest point,

∆U = M2•g•y2 + M1•g•y1

Note, at the lowest point, the mass 1 is 40cm (0.4m) form the midpoint, Also, the mass 2 is -40cm(-04m) from the midpoint

∆U = M2•g•y2 + M1•g•y1

∆U=0.05•9.81•(-0.4) + 0.02•9.82•0.4

∆U=-0.1962+0.07848

∆U=-0.11772 Nm

Now, the moment of inertia of the rod is given as

I=∫r²dm

dm=2pdr

I= 2p∫r²dr

I= 2 × 0.12/0.8 ∫r²dr; from r=0 to 0.4

I=0.3 [r³/3] from r=0 to 0.4

I= 0.3 [ 0.4³/3 -0] ,from r=0 to 0.4

I=0.3 × 0.02133

I=0.0064kg/m².

calculating of inertia of the end masses.

I(1+2)=Σmr² = (m1+m2)r²

I(1+2)=(0.02+0.05)0.4²

I(1+2)=0.07×0.4²

I(1+2)=0.0112 kg/m²

Now, the Energy of the masses due to angular velocity is given as

K.E=½ (I + I(1+2))w²

K.E=½(0.0064+0.0112)w²

K.E= 0.0088w²

Using conservation of energy

The potential energy is equal to the kinetic energy of the system

K.E=P.E

0.0088w²=0.11772

Then, w²=0.11772/0.0088

w²=13.377

w=√13.377

w=3.66rad/s

Then, the relationship between linear velocity and angular velocity is given by

v=wr

v=3.66×0.4

v=1.463m/s

The required linear speed is 1.46m/s approximately

8 0

3 years ago

A sodium has an atomic number of 11 and the atomic mass of 23. Determine the its proton, electrons, and neutrons

ioda

The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass). Sodium has a mass number of 23amu. Since sodium has 11 protons, the number of neutrons must be 23 – 11 = 12 neutrons.

7 0

3 years ago