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AysviL [449]
3 years ago
7

In this lab, you will observe current induced through the interaction of a magnet and wire coil, while changing one property of

the magnet. Which broad question are you investigating by doing this experiment?
Physics
2 answers:
ycow [4]3 years ago
7 0

Answer:

How does magnet polarity affect the current flowing in a loop of wire?

Explanation:

thats the sample response btw

Brrunno [24]3 years ago
5 0

Answer:

How does magnet polarity affect the current flowing in a loop of wire?

Explanation:

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Solve each of the following problems to 3 sig figs and correct Sl units, showing all work.
Salsk061 [2.6K]

Answer:

every number to 3 sf = 1) 45.0  2) 250  3) 1.30

Explanation:

your welcome :)

4 0
2 years ago
A positively charged plastic ruler is brought close to a piece paper resting on the desk. The piece of paper was initially neutr
stealth61 [152]

Answer: static electricity

Explanation:

When the plastic ruler is rubbed, friction opposes the motion and causes the transfer of electron from one surface to another such that plastic becomes negatively charged. When ruler is brought nearer to the paper, it induces the   positive charge in the piece of paper.

4 0
2 years ago
Bullets from two revolvers are fired with the same velocity. The bullet from gun #1 is twice as heavy as the bullet from gun #2.
IrinaVladis [17]

Answer:

option C

Explanation:

Let mass of the bullet be m and velocity be v

mass of gun be M and bullet be V

now,

using conservation of momentum for gun 1

(M+m) V' = 2 mv + 3 MV

V' = 0

3 M V = - 2 mv

momentum of gun 1 =- 2 mv---------(1)

now for gun 2

(M+m) V' = mv + MV

V' = 0

M V = - mv

momentum of gun 1 = -mv-----------(2)

dividing equation (1) by (2)

\dfrac{P_m1}{P_m2} = \dfrac{- 2mv}{-mv}

\dfrac{P_m1}{P_m2} = \dfrac{2}{1}

the correct answer is option C

7 0
2 years ago
You are a member of an alpine rescue team and must get a box of supplies, with mass 2.20 kg , up an incline of constant slope an
a_sh-v [17]

Answer:

The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.

Explanation:

It is given that,

Mass of the box, m = 2.2 kg

The box is inclined at an angle of 30 degrees

Vertical distance, d = 3.1 m

The coefficient of friction, \mu=6\times 10^{-2}

Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.

KE=PE+W

\dfrac{1}{2}mv^2=mgh+W

W is the work done by the friction.

W=f\times d

f=\mu mg\ cos\theta

W=\mu mg\ cos\theta\times \dfrac{d}{sin\theta}

W=\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}mv^2=mgh+\dfrac{\mu mgh}{tan\theta}

\dfrac{1}{2}v^2=gh+\dfrac{\mu gh}{tan\theta}

\dfrac{1}{2}v^2=9.8\times 3.1+\dfrac{6\times 10^{-2}\times 9.8\times 3.1}{tan(30)}

v = 8.19 m/s

So, the speed of the box is 8.19 m/s. Hence, this is the required solution.

8 0
2 years ago
A deuteron, 21H, is the nucleus of a hydrogen isotope and consists of one proton and one neutron. The plasma of deuterons in a n
Naddik [55]

Answer:

1917723.40119 m/s

Explanation:

m = Mass of deuteron = (1.637+1.675)\times 10^{-27}=3.312\times 10^{-27}

k = Boltzmann constant = 1.381\times 10^{-23}\ J/K

T = Temperature = 2.94\times 10^8\ K

RMS velocity is given by

V_r=\sqrt{\dfrac{3kT}{m}}\\\Rightarrow V_r=\sqrt{\dfrac{3\times 1.381\times 10^{-23}\times 2.94\times 10^8}{3.312\times 10^{-27}}}\\\Rightarrow V_r=1917723.40119\ m/s

The RMS velocity of the deutrons is 1917723.40119 m/s

8 0
3 years ago
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