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Brilliant_brown [7]
3 years ago
8

Chapter Name :- Vector

Physics
1 answer:
Nonamiya [84]3 years ago
8 0

The value of the speed of the car, for the front glass of the car to get wet, V_c \geq 10 \ m/s.

The given parameters:

  • <em>Speed of the car, = Vc</em>
  • <em>Speed of the rain, = 10 m/s</em>

The relative velocity of the car with respect to the falling rain is calculated as;

V_{C/R} = V_C- V_R

  • If the speed of the car equals the speed of the rain, the rain will fall behind the car.
  • If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.
  • If the speed of the car is greater than speed of the rain, the rain will fall on the car.

Thus, for the front glass of the car to get wet, V_c \geq 10 \ m/s.

Learn more about relative velocity here: brainly.com/question/24337516

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Three resistors are connected in parallel. If placed in a circuit with a 12-volt power supply. Determine the equivalent resistan
Ivan

(a) The equivalent resistance of three parallel resistors is (R₁R₂R₃)/(R₁R₂ + R₁R₃ + R₂R₃).

(b) The total circuit current is 12/R.eq.

(c) The voltage drop across and current in each resistor is IR₁, IR₂ and IR₃.

<h3>Equivalent resistance of three parallel resistors</h3>

The equivalent resistance of three parallel resistors is calculated as follows;

  • Let the first resistor = R₁
  • Let the second resistor = R₂
  • Let the third resistor = R₃

\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_2}\\\\R_{eq} = \frac{R_1R_2R_3}{R_1R_2 + R_2R_3 + R_1R_3}

<h3>Total Circuit Current </h3>

The total circuit current is calculated as follows;

V = IR

I= \frac{V}{R_{eq}} = \frac{12 \ V}{R_{eq}}

<h3>Voltage drop in each resistor</h3>

Voltage drop in resistor 1 = IR₁

Voltage drop in resistor 2 = IR₂

Voltage drop in resistor 3 = IR₃

Learn more about parallel circuit here: brainly.com/question/80537

#SPJ1

3 0
2 years ago
7) A kite 50 ft above the ground moves horizontally at a speed of 4 ft/sec. At what rate is the length of the string increasing
d1i1m1o1n [39]

Imagine a right triangle where the legs represent the horizontal and vertical lengths of the string and the hypotenuse represents the length of the string.

Let us assign some values:

x = horizontal length in feet

50 = vertical length in feet

L = length of the string in feet

Because we are modeling these quantities with a right triangle, we can use the Pythagorean theorem to relate them with the following equation:

L² = x² + 50²

We want to find an equation for the change of L over time, so first differentiate both sides with respect to time t then solve for dL/dt:

2L(dL/dt) = 2x(dx/dt)

dL/dt = (x/L)(dx/dt)

First let's solve for x at the moment in time described in the problem using the Pythagorean theorem:

L² = x² + 50²

Given values:

L = 100ft

Plug in and solve for x:

100² = x² + 50²

x = 86.6ft

Now let's find dL/dt. Given values:

x = 86.6ft, L = 100ft, dx/dt = 4ft/sec

Plug in and solve for dL/dt:

dL/dt = (86.6/100)(4)

dL/dt = 3.46ft/sec

3 0
4 years ago
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