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3 years ago

Physics question about density

Physics

2 answers:

scZoUnD [109]3 years ago

7 0

So the right answer is 4kg/m^3.

Look at the attached picture

Hope it will help you

Good luck on your assignment

ohaa [14]3 years ago

6 0

Answer:

The answer is option 4.

Explanation:

Firstly, you have to convert the mass of tea bagto kilogram as the question wants the unit in kg/m³.

$1000g = 1kg$

$100g = 1kg \div 10$

$100g = 0.1kg$

So the mass of tea bag is 0.1 kg. Next you have to use density formula ρ = mass/volume. Then you have to substitute the values into the formula :

$ρ = \frac{mass}{volume}$

Let mass = 0.1kg,

Let volume = 0.025m³,

$ρ = \frac{0.1}{0.025}$

$ρ = 4kg \: per \: {m}^{3}$

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Why does a bouncing ball rise to a lower height with each bounce

amm1812

There are two main reasons why a bouncing ball rise to a lower height with each bounce: 1) because every time it hits the ground it encounters friction, which slows it down, and every time it rises from the ground it encounters air resistance.

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3 years ago

Read 2 more answers

A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 152 om and makes an angl

aliya0001 [1]

Answer:

D₂= 167,21 cm : Magnitude of the second displacement

β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement

Explanation:

We find the x-y components for the given vectors:

i: unit vector in x direction

j:unit vector in y direction

D₁: Displacement Vector 1

D₂: Displacement Vector 2

R= resulta displacement vector

D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j

D₂= -D₂(i)-D₂(j)

R= 131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j

We propose the vector equation for sum of vectors:

D₁+ D₂= R

-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j

-51.99i+D₂x(i)=103.23i

D₂x=103.23+51.99=155.22 cm

+142.83j-D₂y(j) =+80.65j

D₂y=142.83-80.65=62.18 cm

Magnitude and direction of the second displacement

$D_{2} =\sqrt{(D_{x})^{2} +(D_{y} )^{2} }$

$D_{2} =\sqrt{(155.22)^{2} +(62.18 )^{2} }$

D₂= 167.21 cm

Direction of the second displacement

$\beta = tan^{-1} \frac{D_{y}}{D_{x} }$

$\beta = tan^{-1} \frac{62.18}{155.22 }$

β= 21.8°

D₂= 167,21 cm : Magnitude of the second displacement

β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement

6 0

4 years ago

would it be possible for a small man running fast to have the same kinetic energy as a large man who runs slowly?

Rudiy27

Absolutely. A little bullet can have more kinetic energy than both of them. KE depends on the mass of the object AND the SQUARE of its speed.

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3 years ago

Select the correct answer. Rita is a registered dietician. What does her work entail? A. prescribing medication for clients B. c

yarga [219]

Answer:

Explanation:

The answer is D because:

A) Only doctors are allowed to prescribe medications.

B) Rita is not a chef/cook.

C) Rita is not a personal trainer

D) The job of a dietican is to provide reccomendations to their clients in order for them to implement a healthy lifestyle via consuming what is best for them.

Hope this helps :)

4 0

3 years ago

Jet aircraft maintenance crews are required to wear protective earplugs. Members of a particular crew wear earplugs that reduce

san4es73 [151]

Answer:

the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB

Explanation:

Given the data in the question;

sound intensity reduced by the factor, m = 305

the sound intensity level experienced by the crew members wearing protective earplugs, L = 79 dB

Now, using the expression of sound intensity level;

L = 10log( $I_0$ )

where $I_0$ is the intensity at L level

so we substitute

79 = 10log( $I_0$ )

$I_0$ = $10^{7.9$

Now, expression for actual intensity;

$I$ = m $I_0$

where $I$ is the actual intensity

so we substitute

$I$ = 305 × $10^{7.9$

Next, we write the expression of sound intensity level for reduced intensity;

L' = 10log( $I$ )

So we substitute

L' = 10log( 305 × $10^{7.9$ )

L' = 10log( 24227011159.09058 )

L' = 103.8 dB

Therefore, the sound intensity level for actual intensity ( without the earplugs ) is 103.8 dB

8 0

3 years ago