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Lynna [10]
3 years ago
15

the length and width of a rectangular patio are (x+8) feet and (x+6) feet, respectively. If the area of the patio is 160 square

feet, what are the dimensions of the patio?
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0
<span>(x + 8)  (x + 6) = 160
x² +6x +8x +48 = 160
</span>x² +6x +8x +48 - 160 =0
<span>x² +14x -112=0

You have to calculate the discriminant.

(Please mark be brainliest)

</span>
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I need help please i'll give brainly​
Readme [11.4K]

Answer:

60 +24 = 84

Step-by-step explanation:jjjjjhjhjhj

6 x 4 +5 x 12

7 0
3 years ago
(1.)Find the slope of the line that passes through the given pair of points. (If an answer is undefined, enter UNDEFINED.) (?a +
jekas [21]

Answer:

1. The slope of the line is m=\frac{-2b+3}{2a}.

2. The value of a is 18.

Step-by-step explanation:

If a line passes through two points, then the slope of the line is

m=\frac{y_2-y_1}{x_2-x_1}

(1)

It is given that the line passes through the points (-a + 3, b - 3) and (a + 3, -b). So, the slope of the line is

m=\frac{-b-(b-3)}{a+3-(-a+3)}

m=\frac{-b-b+3}{a+3+a-3)}

m=\frac{-2b+3}{2a}

The slope of the line is m=\frac{-2b+3}{2a}.

(2)

If the line passing through the points (a, 1) and (6, 5), then the slope of the line is

m_1=\frac{5-1}{6-a}=\frac{4}{6-a}

If the line passing through the points (2, 7) and (a + 2, 1), then the slope of the line is

m_2=\frac{1-7}{a+2-2}=\frac{-6}{a}

The slopes of two parallel lines are same.

m_1=m_2

\frac{4}{6-a}=\frac{-6}{a}

On cross multiplication we get

4a=-6(6-a)

4a=-36+6a

4a-6a=-36

-2a=-36

Divide both sides by -2.

a=18

Therefore the value of a is 18.

8 0
3 years ago
What is the first number greater than 106637 where it's tens and units digits are the same
sashaice [31]
The first number after that matching the criteria is 106644, as 33 is below so the closest one has to be at 44.
4 0
3 years ago
Read 2 more answers
Working together, Katherine and Marina can sand a large cabinet in 2 hours. It would take Katherine 10 hours to do the job alone
timofeeve [1]

I'm not sure what you're asking but they each took 5 hours of work into one hour..

5 0
3 years ago
In the figure, point k is the image of point j under a reflection across line L. Find y
Viktor [21]
Since, <span>point K is the image of point J under a reflection across line L.

The distance, JM = MK

</span>Hence, 2x + 4 = 4x - 6
4x - 2x = 4 + 6
2x = 10
x = 5

Also refrection of a point across a line form an angle of 90 degrees at the point of refrection.
i.e. 3y - 30 = 90
3y = 90 + 30 = 120
y = 120 / 3 = 40

Therefore, the value of y is 40.
4 0
3 years ago
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