All categories

3 years ago

Explain your answer

2 answers:

7 0

$(4w^2-7w-6)-(8w^2+2w-3)\\ -(a\pm b)=-1(a\pm b)\ \ \ \ |use\ a\ distributive\ property: a(b\pm c)=ab\pm ac\\\\\=4w^2-7w-6-8w^2-2w-(-3)\\\\ = 4w^2-7w-6-8w^2-2w-(-3)\\\\=(4w^2-8w^2)+(-7w-2w)+(-6+3)\\\\=\boxed{-4w^2-9w-3}$

Nataliya [291]3 years ago

6 0

(4w² - 7w - 6) - (8w² + 2w - 3)
(4w² - 8w²) + (-7w - 2w) + (-6 + 3)
-4w² - 9w - 3
The answer is A.

You might be interested in

Elimination method 3x + -3 =6 3x + 2y = 16

zheka24 [161]

Answer:

(4,2)

Step-by-step explanation:

hope this answerss

3 0

3 years ago

Solve 10/12 - 3/8 show your solution as an equation

elena55 [62]

Answer:

11/24

Step-by-step explanation:

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator. Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1. The two fractions now have like denominators so you can subtract the numerators.

This fraction cannot be reduced.

Therefore the answer is 11/24

7 0

3 years ago

Read 2 more answers

A cylinder with 3 radius and and height is 2 inches what is the volume?

VashaNatasha [74]

Answer:

$\huge\boxed{\sf V = 56.5 \ in.^3}$

Step-by-step explanation:

Radius = r = 3 in.

Height = h = 2 in.

Volume:

$\sf Volume \ of \ the \ cylinder = \pi r^2 h\\\\V = (3.14)(3)^2(2)\\\\V =(3.14)(9)(2)\\\\V = (3.14)(18)\\\\V = 56.5 \ in.^3\\\\\rule[225]{225}{2}$

3 0

2 years ago

This is a Differential Equations problem, I only need help on part 1 from question five. I need steps as well, thank you.

jolli1 [7]

Answer:

a) $y(t) = \sqrt{2t + 1 }$

b) 1.5 hours after thickness will be 2 inches.

Step-by-step explanation:

$\frac{dy}{dt} = \frac{1}{y} \\ \\ ydy = dt \\ \\ integrating \: both \: sides \\ \\ \int y \: dy = \int 1 \: dt \\ \\ \frac{ {y}^{2} }{2} = t + c \\ \\ {y}^{2} = 2t + 2c \\ \\ y (t)= \sqrt{2t + 2c} ...(1) \\ \\ a) \: \: \: plug \: t = 0 \: in \: (1) \\ \\ y (0)= \sqrt{2(0) +2 c} \\ \\ y (0)= \sqrt{0 +2 c} \\ \\ 1 = \sqrt{2c} \: \: ( \because \: y (0)=1) \\ \\ 2c = 1 \: \implies \: c = \frac{1}{2} \\ \\ plug \: c = \frac{1}{2} \: in \: (1) \\ \\ y(t) = \sqrt{2t + 2 \times \frac{1}{2} } \\ \\ \huge \: \red {y(t) = \sqrt{2t + 1 } } \\ \\b) \: \: plug \: y(t) = 2 \: in \: above \: equation \\ \\ 2 = \sqrt{2t + 1} \\ \\ 4 = 2t + 1 \: \\ (squaring \: both \: sides) \\ \\ 4 - 1 = 2t \\ \\ 2t = 3 \\ \\ t = \frac{3}{2} \\ \\ t = 1.5 \: hours \\$

6 0

2 years ago

Please help I will give 10 points answer both questions

seropon [69]

Question 4:
18(A)+7(S)+10(G)=35 lollipops
35/10=3.5
35/18=1.99(repeating)
35/7=5

I hope that helps in some way.

5 0

3 years ago